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Gelneren [198K]
3 years ago
13

Jordan can swim to laps in 4 1/2 minutes select the correct unit rate for the given situation.

Mathematics
1 answer:
bonufazy [111]3 years ago
4 0

Answer:

Step-by-step explanation:

4 1/2 minutes = 4.5 minutes

2 / 4.5 = 0.44 laps per minute

OR

4.5 / 2 = 2.25 minutes per lap

not sure which one ur looking for...but both are unit rates

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Pleaseeeew HELPPPP no one ever answers my questions on here
Delvig [45]

Answer:

Circumfrence: 40.21

Radius: 6.4

Step-by-step explanation:

For radius, you only have to divide the diameter (in this case 12.8) by 2 which gives us 6.4

For Circumference, plug in the radius in the formula C=2π(6.4), and that gives us 40.21

3 0
3 years ago
This is just for a brainiest
Veseljchak [2.6K]

Answer:

panfide

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Suppose you have two squares, one of which is larger than the other. Suppose further that the side of the larger square is twice
TEA [102]

Answer:

Area of smaller square: y^2 yards^2,

area of larger square: 4*y^2 yards^2.

Step-by-step explanation:

If the smaller square has a side which length is y yards, its area can be calculated as the square of its side, so:

Area of smaller square = y^2

If the larger square has a side which length is twice as long as the side of the smaller square, its side is equal to 2*y yards, so its area will be:

Area of larger square = (2*y)^2 = 4*y^2

So the area of the smaller square is y^2 yards^2, and the area of the larger square is 4*y^2 yards^2.

6 0
3 years ago
10 cups Equals how many pt
ValentinkaMS [17]
The answer you are looking for is 5
7 0
4 years ago
A clothing store has a rectangular clearance section with a length that is twice the width w. During a sale, the section is expa
frosja888 [35]

Answer:

see the explanation

Step-by-step explanation:

step 1

The original area of the rectangular clearance section is equal to

A=LW ----> equation A

we know that

The length is twice the width

L=2W ----> equation B

substitute equation B in equation A

A=(2W)W

A=2W^2\ ft^2

step 2

During a sale, the section is expanded to an area of

A=(2W^2+11W+12)\ ft^2

so

To find out the amount of the increase in the length and width of the clearance section, subtract the areas

(2W^2+11W+12)\ ft^2-2W^2\ ft^2=(11W+12)\ ft^2

therefore

The amount of the increased area is (11W+12)\ ft^2

5 0
3 years ago
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