Question

Suppose you have two squares, one of which is larger than the other. Suppose further that the side of the larger square is twice as long as the side of the smaller square. If the length of the side of the smaller square is y yards, give the area of each square.

Answer 1

Answer:

Area of smaller square: y^2 yards^2,

area of larger square: 4*y^2 yards^2.

Step-by-step explanation:

If the smaller square has a side which length is y yards, its area can be calculated as the square of its side, so:

Area of smaller square = y^2

If the larger square has a side which length is twice as long as the side of the smaller square, its side is equal to 2*y yards, so its area will be:

Area of larger square = (2*y)^2 = 4*y^2

So the area of the smaller square is y^2 yards^2, and the area of the larger square is 4*y^2 yards^2.