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Yuliya22 [10]
3 years ago
13

∠A=6x+5 ∘ space, start color blueD, angle, A, equals, 6, x, plus, 5, degree, end color blueD \qquad\green{\angle B=4x + 45^\circ

}∠B=4x+45 ∘ space, start color green, angle, B, equals, 4, x, plus, 45, degree, end color green Solve for xxx and then find the measure of \blueD{\angle A}∠Astart color blueD, angle, A, end color blueD: \blueD{\angle A} =∠A=start color blueD, angle, A, end color blueD, equals ^\circ ∘ degree Stuck?Watch a video or use a hint.

Mathematics
1 answer:
anyanavicka [17]3 years ago
5 0

Answer:

Step-by-step explanation:

Find the required figure in the attachment. From the figure, <A = <B (alternate interior angle)

Given

∠A=6x+5

∠B=4x+45

Since <A = <B hence;

6x+5 = 4x+45

Collect the like terms

6x-4x = 45-5

2x = 40

Divide both sides by 2;

2x/2 = 40/2

x = 20

Hence the value of x is 20°

Next is to get the measure of <A

Since <A = 6x+5

Substitute x = 20° into the expression

<A = 6(20)+6

<A = 120+6

<A = 126°

Hence the measure of <A is 126°

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