Answer:
14
or 
Step-by-step explanation:
Turn your fractions into improper and make them have the same denominator
+
=
Leave it as is or simplify to 14
The extreme values of the function f(x) = x - 4sqrt(x) occur at the values of x for which f'(x) = 0
f'(x) = 1 - 2/sqrt(x) = 0
sqrt(x) - 2 = 0
sqrt(x) = 2
x = 4
To check for minimum or maximum,
f''(x) = 1/(sqrt(x))^3 = 1/(sqrt(4))^3 = 1/(2^3) = 1/8 => the point is a minimum.
Therefore, the minimum value = f(4) = 4 - 4sqrt(4) = 4 - 4(2) = 4 - 8 = -4 and occurs at x = 4.
Answer:
{f|0 ≤ f(x)}; x² - 4x + 5
Step-by-step explanation:
To find the Quadratic Equation, plug the <em>vertex</em> into the Vertex Equation FIRST, <em>y = </em><em>a</em><em>(</em><em>x</em><em> </em><em>-</em><em> </em><em>h</em><em>)</em><em>²</em><em> </em><em>+</em><em> </em><em>k</em>, where (<em>h</em><em>,</em><em> </em><em>k</em>) → (<em>2,</em><em> </em><em>1</em>)<em> </em>is the vertex, plus, -h gives you the OPPOSITE terms of what they really are, and k gives you the EXACT terms of what they really are: (x - 2)² + 1. Doing this will give you the Quadratic Equation of <em>x² - 4x + 5</em>. You understand now?
I am joyous to assist you anytime.
List out the multiples of 8
8, 16, 24, 32, 40, 48, 56, 64, 72, 80
I'm going to highlight in bold the values between 20 and 50
8, 16, 24, 32, 40, 48, 56, 64, 72, 80
So the favorable outcomes, aka the outcomes we want, are: {24, 32, 40, 48}
These four values are all divisible by 8. Also, these values are between 20 and 50.
