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3 years ago

8

Use substitution and graphing to determine the solution to the following system of equations:

1 answer:

dybincka [34]3 years ago

4 0

$y=-\frac{1}{2} \\x=\frac{2}{3}$

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Plz help me I can't get these wrong plz help meeeee

Vika [28.1K]

Answer: w<0

Step-by-step explanation:

4 0

3 years ago

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The boeing 747 airplane is 250 feet in length. If a model of this plane is 8 inches long , what scale was used to create this mo

cluponka [151]

Answer: The wingspan is 36 m.

Using a proportion to solve this, we write the scale factor as a ratio first: 19/38, since 19 is the size of the model's length and 38 is the real length. For the second ratio, we have 18 for the size of the model wingspan and x for the real wingspan:

19/38 = 18/x

Cross multiply:

19*x = 38*18

19x = 684

8 0

3 years ago

Jen has 6 crayons. Lisa has 3 crayons. Max has 1 more crayon than lisa. How many did they all have together

Dmitry [639]

Jen has 6 crayons

Lisa has 3 crayons

Max has = lisa +1 = 4 crayons

Jen + Lisa + Max = 6+3+4 = 13 crayons

Answer: 13 crayons

4 0

3 years ago

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A strobe light is located at the center of a square dance room. the rotating light is 40 feet from each of the square walls and

Effectus [21]

The equation of the rotating light is an illustration of a secant function

The equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

<h3>How to determine the equation</h3>

The equation is a secant function represented by

$y =A\sec(Bt)$

Where:

A represents the amplitude

So, we have:

$A = 40$ --- the distance of the light from each square wall

B represents the period, and it is calculated as:

$B = \frac{2\pi}{T}$

The light completes its full rotation every 6 seconds.

This means that,

T = 6

So, we have:

$B = \frac{2\pi}{6}$

Simplify

$B = \frac{\pi}{3}$

Substitute values for A and B in $y =A\sec(Bt)$

$y = 40\sec(\frac{\pi}{3}t)$

Rewrite as a function

$d(t) = 40\sec(\frac{\pi}{3}t)$

Hence, the equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

Read more about trigonometry functions at:

brainly.com/question/1143565

5 0

3 years ago

2. In the figure, what is m ZC? (1 point)<br> 15°<br> 35°<br> 50°<br> 65°

Doss [256]

Answer:

35°

Step-by-step explanation:

By the property of intersecting secants outside of a circle.

$m\angle C = \frac{1}{2} \times (100° - 30°)\\\\m\angle C = \frac{1}{2} \times 70°\\\\\huge \red {\boxed {m\angle C = 35°}}$

3 0

3 years ago