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3 years ago

Solve log x − 1 16 = 4.

1 answer:

3 0

I hope this helps you

log(x-1)4^2=4

2.log (x-1)4=4

log (x-1)4=2

log (x-2)2^2=2

2log (x-1)2=2

log (x-1)2=1

[logab=y b=a^y]

b=2 a=x-1 y=1

2=(x-1)^1

x-1=2

x=3

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Write 53 hundreds in standard form

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The answer is (−12714

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3 years ago

2x^2-5x+6 divided by x-3

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Answer:

Step-by-step explanation:

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2 years ago

A family wants to save for college tuition for their daughter. What continuous yearly interest rate r% is needed in their saving

sergey [27]

Answer:

The continuous yearly interest is 22.5% per year.

Step-by-step explanation:

Continuous yearly interest:

Continuous yearly interest is defined as the sum of the interest comes from principle and the interest comes from interest.

The formula for continuous interest yearly is

$A=Pe^{rt}$

where A = The final amount =$110,000

P= principle =$4,700

r= rate of interest

t= time (in year)= 14 years

$\therefore 110,000= 4,700e^{r\times 14}$

$\Rightarrow e^{14r}= \frac{110,000}{4,700}$

Taking ln both sides

$\Rightarrow ln e^{14r}= ln(\frac{110,000}{4,700})$

$\Rightarrow {14r}= ln(\frac{1100}{47})$

$\Rightarrow r=\frac{ln( \frac{1100}{47})}{14}$

$\Rightarrow r = 0.225$ (approx)

The continuous yearly interest is 0.225 = 22.5% per year.

4 0

3 years ago

The length of the base of an isosceles triangle is x. The length of a leg is 4x-6. The perimeter of the triangle is 96. Find x.

slava [35]

Answer:

12 units

Step-by-step explanation:

base is x

one of the legs measure 4x-6

therefore, perimeter is equal to

2 (4x - 6) + x = 96

8x - 12 + x = 96

9x = 96 + 12

9x = 108

x = 108/9 = 12 units

5 0

3 years ago

Uranus moves in an elliptical orbit with the sun at one of the foci. The length of the half of the major axis is 2,876,769,540 k

Alina [70]

Answer:

The minimum distance (perihelion) of Uranus from the sun is 2,749,040,972.

Step-by-step explanation:

Consider the provided information.

The length of the half of the major axis is 2,876,769,540 kilometers, and the eccentricity is 0.0444.

The eccentricity (e) of an ellipse is the ratio of the distance from the center to the foci (c) and the distance from the center to the vertices (a).

$e=\frac{c}{a}$

Substitute a = 2,876,769,540 and e = 0.0444 in above formula and solve for c.

$0.0444=\frac{c}{2,876,769,540 }$

$c=127728567.576$

Minimum distance of Uranus from the sun is:

$a-c=2,876,769,540-127728567.576\\a-c=2749040972.424\approx2749040972$

Hence, the minimum distance (perihelion) of Uranus from the sun is 2,749,040,972.

6 0

3 years ago