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3 years ago

I NEED HELP ASAP PLEASEEE! No links or your reported, Thanks.

Mathematics

1 answer:

sashaice [31]3 years ago

3 0

5/4 is the slope I believe

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How many solutions does this linear system have?

alexira [117]

The answer here is no solution

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2 years ago

PLEASE HELPPPP MEEE, PLEASE ANSWER ALL OF THE QUESTIONS!!!!!

Sophie [7]

Answer:

What question?

Step-by-step explanation:

I don't see a question do you?

5 0

3 years ago

Read 2 more answers

Construct a 95% confidence interval for the population mean, μ. Assume the population has a normal distribution. A random sample

GuDViN [60]

Answer: $(628.48,\ 661.52)$

Step-by-step explanation:

Given : Sample size : $n=16$ , which is a small sample (, 30) so we use t-test.

Sample mean : $\overline{x}=645 \text{ hours}$

Standard deviation : $\sigma = 31 \text{ hours}$

Significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=2.131$

The confidence interval for population mean is given by :-

$\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=645\pm(2.131)\dfrac{31}{\sqrt{16}}\\\\\approx645\pm16.52\\\\=(645-16.52,\ 645+16.52)\\\\=(628.48,\ 661.52)$

Hence, a 95% confidence interval for the population mean $\mu$ = $(628.48,\ 661.52)$

6 0

3 years ago

A direct variation function contains the points (–9, –3) and (–12, –4). Which equation represents the function?

vladimir1956 [14]

Answer: third option.

Step-by-step explanation:

By definition, a direct variation function has the form shown below:

$y=kx$

Where k is a constant.

Then, knowing the given points, you can calculate k with the formula for calculate the slope of a line:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-4-(-3)}{-12-(-9)}=\frac{1}{3}$

Substituting k into $y=kx$ , you obtain:

$y=\frac{1}{3}x\\\\y=\frac{x}{3}$

4 0

3 years ago

Graph the function: f(x) = -2 for x < 1. ASAP!! YOU CAN USE A ONLINE TOOL TO GRAPH AND TAKE SCREENSHOT (I would but i dont kn

chubhunter [2.5K]

Answer:

please see attachhment

Step-by-step explanation:

Hope this helps!

7 0

2 years ago