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3 years ago

Evaluate 2 + 6(9-3^2)-2

Mathematics

1 answer:

8_murik_8 [283]3 years ago

6 0

Answer:

Step-by-step explanation:

2+ 6(9-3^2)-2

3^2 = 3 x 3 = 9

2+ 6(9 - 9)-2

9-9 = 0

2 + 6(0) -2

6(0) = 0

2+ (-2) = 0

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Determine the slope of the line that passes through each pair of points.

Soloha48 [4]

$1.)\\\\(5,1) \ \ and \ \ (2,7)\\\\First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{ 7-1}{2-5} = \frac{6}{-3}=-2 \\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1}) \\ \\m=-2 , \ \x_{1}=5, \ \ y_{1}=1 \\ \\y-1 = -2(x-5 ) \\\\y=-2x+10+1 \\ \\y=-2x+11$

$2.)\\\\(5,3)\ \ and \ \ (-2,3)\\\\First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{ 3-3}{-2-5} = \frac{0}{-7}=0\\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1}) \\ \\m=0 , \ \x_{1}=5, \ \ y_{1}=3 \\ \\y-3 = 0\cdot (x-5 ) \\\\y-3=0 \\ \\y=3$

7 0

3 years ago

A collection of dimes and quarters is worth $10.45. There are 70 coins in all. Find how many of each there are

Advocard [28]

There are 47 dimes and 23 quarters.

Step-by-step explanation:

Total amount = $10.45 = 10.45*100 = 1045 cents

Total coins = 70

1 dime = 10 cents

1 quarter = 25 cents

Let,

Dimes = x

Quarters = y

According to given statement;

x+y=70 Eqn 1

10x+25y=1045 Eqn 2

Multiplying Eqn 1 by 10;

$10(x+y=70)\\10x+10y=700\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(10x+25y)-(10x+10y)=1045-700\\10x+25y-10x-10y=345\\15y=345$

Dividing both sides by 15;

$\frac{15y}{15}=\frac{345}{15}\\y=23$

Putting y=23 in Eqn 1

$x+23=70\\x=70-23\\x=47$

There are 47 dimes and 23 quarters.

Keywords: linear equations, subtraction

Learn more about linear equations at:

#LearnwithBrainly

6 0

3 years ago

Please help me thank you!!!

kow [346]

There are two acceptable ways of solving this. I'll show both (just in case one of them doesn't align with the information from your textbook).

Option 1 (fast and easy):

The following is the equation for the area of a regular pentagon with side length s.

$A= \dfrac{s^2}{4} \times \sqrt{5(5+2\sqrt{5})}$

Plug s=12 into the equation.

$A= \dfrac{12^2}{4} \times \sqrt{5(5+2\sqrt{5})}$

$\approx 247.7$

The third choice should be your answer.

Option 2 (much more complicated):

The area of a regular polygon can be solved with the following formula.

$A=\dfrac{\text{perimeter} \times \text{apothem}}{2}$

Let's solve for the apothem.

A pentagon can be divided into 5 congruent isosceles triangles. The vertex angle will be 360/5, or 72 degrees.

An isosceles triangle can be divided into two right triangles. One of the angles of the right triangle will be 72/2, or 36 degrees.

The leg opposite of the 36 degree angle will be 12/2, or 6 inches long.

$\text{apothem}=\dfrac{6}{\tan{36}}$

$\approx 8.26$

The apothem is about 8.26 inches.
The perimeter is 12*5, or 60 inches.

$A=\dfrac{\text{perimeter} \times \text{apothem}}{2}$

$=\dfrac{60 \times 8.26}{2}$

$\approx 247.8$

(it seems that we're off by 0.1 due to rounding errors)

The answer is the third choice. Hope this helps! :)

4 0

3 years ago

Bertha and Vernon are competing in a diving competition. Bertha's dive ended -40 m from the starting platform. Vernon's dive end

masya89 [10]

Answer:

8 times farther

Step-by-step explanation:

Hi! I hope this is right....:)

-40 / -5 = 8

The answer should be 8. idk

Let me know if it was right or not....

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4 years ago

Quinn correctly answered 72 questions on a test, getting a score of 80%. How many questions were on the test?

vesna_86 [32]

93 hope this helps thank u

8 0

3 years ago

Read 2 more answers