Given the altitude of an equilateral triangle is 12 cm, find the exact perimeter of the triangle
1 answer:
<span>The altitude of an equilateral triangle bisects one of the angles and the opposite side.
So, let </span>a be<span> the altitude of the triangle; we have the formula </span><span>a=xsinθ</span><span>, where </span>x<span> is the side of the triangle. Solving for </span>x<span>, </span><span>x=<span>a / <span>sinθ;
a = 12 cm; </span></span></span>θ = 60 degrees;
So, x =
<span>The exact perimeter of the triangle is 3x;
</span>
<span>
</span>
So, let </span>a be<span> the altitude of the triangle; we have the formula </span><span>a=xsinθ</span><span>, where </span>x<span> is the side of the triangle. Solving for </span>x<span>, </span><span>x=<span>a / <span>sinθ;
a = 12 cm; </span></span></span>θ = 60 degrees;
So, x =
<span>The exact perimeter of the triangle is 3x;
</span>
</span>
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