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jarptica [38.1K]
4 years ago
5

2 (x+6) + 3x + 4 = ?

Mathematics
2 answers:
ra1l [238]4 years ago
8 0

2(x+6) + 3x + 4

2x + 12 + 3x + 4

5x + 16

i think 5x + 16 would be the answer

hopefully this helps

guajiro [1.7K]4 years ago
6 0

Answer:hope we can be friends can i please get brainliest

Simplifying

2x + 6 = 3x + 4

Reorder the terms:

6 + 2x = 3x + 4

Reorder the terms:

6 + 2x = 4 + 3x

Solving

6 + 2x = 4 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

6 + 2x + -3x = 4 + 3x + -3x

Combine like terms: 2x + -3x = -1x

6 + -1x = 4 + 3x + -3x

Combine like terms: 3x + -3x = 0

6 + -1x = 4 + 0

6 + -1x = 4

Add '-6' to each side of the equation.

6 + -6 + -1x = 4 + -6

Combine like terms: 6 + -6 = 0

0 + -1x = 4 + -6

-1x = 4 + -6

Combine like terms: 4 + -6 = -2

-1x = -2

Divide each side by '-1'.

x = 2

Simplifying

x = 2

Step-by-step explanation:

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14.       1.5, 10    <- Answer
15.       5,1          <- Answer

Proof 14 

Solve the following system:
{2 x - y = -7 | (equation 1)
4 x - y = -4 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -4 | (equation 1)
2 x - y = -7 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x - y = -4 | (equation 1)
0 x - y/2 = -5 | (equation 2)
Multiply equation 2 by -2:
{4 x - y = -4 | (equation 1)
0 x+y = 10 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = 6 | (equation 1)
0 x+y = 10 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3/2 | (equation 1)
0 x+y = 10 | (equation 2)
Collect results:
Answer: {x = 1.5               
                y = 10

Proof 15. 

Solve the following system:
{5 x + 7 y = 32 | (equation 1)
8 x + 6 y = 46 | (equation 2)
Swap equation 1 with equation 2:
{8 x + 6 y = 46 | (equation 1)
5 x + 7 y = 32 | (equation 2)
Subtract 5/8 × (equation 1) from equation 2:{8 x + 6 y = 46 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 23 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Multiply equation 2 by 4/13:
{4 x + 3 y = 23 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 20 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 5 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer:  {x = 5                           y = 1
8 0
3 years ago
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