Can someone please write the equation for this?

Does anybody know anything about linear functions?

Daniel [21]

Depends on what the question is , if you tell me I may can help you .

3 0

3 years ago

The germination rate is the rate at which plants begin to grow after the seed is planted.

chubhunter [2.5K]

Answer:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

Step-by-step explanation:

Data given and notation

n=15 represent the random sample taken

X=7 represent the number of seeds germinated

$\hat p=\frac{7}{15}=0.467$ estimated proportion of seeds germinated

$p_o=0.9$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of germinated seeds is less than 0.9 or 90%.:

Null hypothesis: $p\geq 0.9$

Alternative hypothesis: $p < 0.9$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

4 0

3 years ago

What are some items that are less than 1 ounce<br> What are some items that weigh more than 1 ton

Ket [755]

Less than 1ounce: Feather, grain of sand, grain of sugar

more than 1 ton: Car,house,train

7 0

3 years ago

You receive two quarters, one dime, and four pennies back in change. Write the amount as a fraction in simplest form

Ahat [919]

$\frac{50}{100} = \frac{2}{4} = \frac{1}{2}$
$\frac{10}{100} = \frac{1}{10}$
$\frac{4}{100} = \frac{2}{50} = \frac{1}{25}$
$\frac{1}{2} = .50$
$\frac{1}{25} = .04$
$\frac{1}{10} = .10$

7 0

3 years ago

Read 2 more answers

If (-7,43) and (4,-12) are two anchor points on the trend line, then find the equation of the line

Romashka [77]

Slope, found using the points is -55/11 = -5
We use that for the equation y=mx+b where m=-5. Since we also know one of the points, we can plug that in and find b
-12=-5(4)+b
-12=-20+b
8=b

So the equation of the line is y=-5x+8

8 0

3 years ago