V = d/t = 8.8 miles/[80/60] hours = 6.6 miles/hour
t = d/v = d/6.6
Answer: d/6.6, where d is the number of miles to run.
The answer is by using the measuring tape
So the first hour it travels from 1-6 miles, the second hour it travels at least two miles. And the question is "draw the range of miles the boat could of traveled in the second hour". Well first of all the third hour is completely useless so forget about that. Now, the first hour says it traveled from 1-6 miles, we don't know how many miles it traveled for sure but it could of traveled up to 6. So in the second hour when they say "at least two miles" the boat could of travled at least two miles more than 1-6. So 1+2+3, 2+2+4, 3+2=5, 4+2=6, 5+2=7 and 6+2=8. So the boat could of traveled from 3 to 8 miles in the second hour.
Answer:
See proof below
Step-by-step explanation:
One way to solve this problem is to "add a zero" to complete the required squares in the expression of xy.
Let 
and 
with 
. Multiplying the two equations with the distributive law and reordering the result with the commutative law, we get 
Now, note that 
by the commutativity of rational integers. Add this convenient zero the the previous equation to obtain 
, thus xy is the sum of the squares of 
.
