Answer:
D
Step-by-step explanation:
It's one of each or not both tho:)
Answer:
1.) There are 16 juniors and 8 seniors in the Chess Club. If the club members decide to send 9 juniors to a tournament, how many different possibilities are there?
(16 over 9) = 16!/(9!*7!) = 11440
2.) How many different ways can 3 cards be drawn from a deck of 52 cards without replacement?
52*51*50 = 132600
3.) How many different ways can 3 cards be drawn from a deck of 52 cards with replacement?
52^3 = 140608
4.) A corporation has 5 officers to choose from which 3 are selected to comprise the board of directors. How many combinations are there?
(5 over 3) = 5!/(3! * 2!) = 10
5.) A combination lock has the numbers 1 to 40 on each of three consecutive tumblers. What is the probability of opening the lock in ten tries?
10/40^3 = 1/6400
Just matter of combining like terms
6x - 7 - 11x + x =
(6x + x - 11x) - 7 =
(7x - 11x) - 7 =
- 4x - 7 <===
Answer:
Correct option: B
Step-by-step explanation:
The professor can perform a One-mean <em>t</em>-test to determine whether the average score of the students in his class is more than the average score of all the students attending university.
A <em>t</em>-test will be used instead of the <em>z</em>-test because the population standard deviation is not provided instead it is estimated by the sample standard deviation.
The hypothesis for this test can be defined as follows:
<em>H₀</em>: The average score of the students in his class is not more then the entire university, i.e. <em>μ ≤ 35</em>.
<em>Hₐ</em>: The average score of the students in his class is more then the entire university, i.e. <em>μ > 35</em>.
Given:

The test statistic is:

Thus, the correct option is (B).