Answer:
Step-by-step explanation:
Hello
I believe there is an error in the question
we have two equations and need to find x and y

let s multiply by 8 so that we can get rid of the fractions
(1) becomes 2x+4y=5
(2) becomse 6x-4y=9
if we sum it gives
2x+4y+6x-4y=9+5
8x=14
x = 14/8 = 7/4
and then from the first equation
4y = 5 - 7/4
<=> 16y = 20-7 = 13
y = 13/16
the solutions is (7/4,13/16)
Answer:
10.0
Step-by-step explanation:
see attached for reference.
given two points in the x-y axis (x₁, y₁) and (x₂, y₂)
the distance bettween them is given by
Distance, D = √ ( (x₂-x₁)² + (y₂-y₁)² )
In our case we are given points (9,10) and (-1,9)
substituting these into the formula , we get:
D = √ ( (9-10)² + (-1-9)² )
= √ ( (-1)² + (-10)² )
= √ ( 1 + 100 )
=√101
= 10.04988
= 10.0 (rounded to nearest tenth)
Just add 5 on both sides:
x-5>10
x>15
Answer:
X=5
Step-by-step explanation:
Answer: 22 attendees can attend the corporate team-building event, with a budget of $46.
1. 8 = 4x
2. 8/4 = 4x/4
3. x = 2, each ticket would cost $2 per attendee
4. $46/$2 = 23