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babymother [125]
3 years ago
5

PLEASE HELP FAST Segment PR and segment QS are diameters of circle U. Find measure of arc ST

Mathematics
1 answer:
kogti [31]3 years ago
5 0

Answer:

Maybe 74

Step-by-step explanation:

42+64=106

180-106=74

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What is the range of the relation of centimeters as a function of inches? {5.08, 10.16, 17.78, 25.4, 33.02} all positive integer
mel-nik [20]

Answer:

y>0 Option D

Step-by-step explanation:

4 0
3 years ago
a geometric series where the first term is -12, the last term is -972, and each term after the first is triple the previous term
Luba_88 [7]

Answer:

the geometric series is a(n) = -12(3)^(n-1)

Step-by-step explanation:

"Triple" denotes multiplication by 3.  Thus, the common factor here is 3.

The general formula for a geometric series is a(n) = a(1)(r)^(n-1), where a(1) is the first term, r is the common ratio.

Here, we have a(n)= (-12)(3)^(n-1) = -972.

We need to solve this for n, which represents the last term.

The first step towards solving for n is to divide both sides by -12:

3^(n-1) = 81

To solve for n-1, rewrite 81 as 3^4.  Then we have:

3^(n-1) = 3^4, implying that (n-1) = 4 and that n = 5.

Then we know that it is the 5th term that equals -972.

In summary, the geometric series is a(n) = -12(3)^(n-1).

8 0
3 years ago
Use the graph to write a formula for the polynomial function of the least degree
Neporo4naja [7]

Answer:

0.5 degrees is the answer you divided the quotion by 5 then get your answer (this isnt actually the answer lol)

Step-by-step explanation:

3 0
3 years ago
How can the quotient for problem 2 help you find the quotient for problem 3 ? Problem 2:5 divided by 20 =4 & problem 3: 4 di
ozzi
It helps you because it's the same fact family
8 0
3 years ago
What are the trigonometric ratios of in a right triangle with the given value tan A = 9/40
hjlf

The trigonometric ratios of the right triangle with the given value tan A = 9 / 40 are

sin A = 9 / 41

cos A = 40 / 41

<h3>Trigonometric ratios</h3>

Trigonometric ratios are used to solve for the sides and angles of a right angle triangle.

Therefore,

sin A = opposite / hypotenuse

cos A = adjacent / hypotenuse

tan A = opposite / adjacent

Using Pythagoras theorem, let find the hypotenuse side

c² = 40² + 9²

c = √1681

c = 41

Therefore,

sin A = 9 / 41

cos A = 40 / 41

learn more on trigonometric ratios here: brainly.com/question/24320387

#SPJ1

8 0
2 years ago
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