Given :
Amount, A = 5760 Rs.
Interest in the amount, I = 1526 Rs.
To Find :
We need to find the % rate of interest.
Solution :
Let, us assume it is simple interest.
So,
Hence, this is the required solution.
Sample space is 36C4
Now, we want to know all of the combinations that have 1 digit in it.
So, we can have one here:
1XXX
X1XX
XX1X
XXX1
But we have 10 different digits to choose from. So, we need to introduce the combination term, nCr, where n is a list of all digits and r is how many we want.
Since we only want one, we will need 10C1 for the number of digits. But we need to choose three lowercases, so it becomes 10C1 × 26C3
Since it's a probability question, we need to divide that by our sample space, 36C4, and our percentage becomes 44%
So we just need to raise the pool back to original level
in total, the pool drained a total of 1 and 3/8 inches
so we need to find out how long it would take to raise the pool by 1 and 3/8 inches
1 inch=320 gallons
1 and 3/8=320 times 1 and 3/8=320 and 960/8=440
he needs to put in 440 gallons
it is 5.75 gallons per minute
find out how many minutes it will take
440=5.75 times x minutes
divide both sides by 5.75
76.521=xminutes
round
77 minutes
1 hour=60 minutes
77>60
it will take more than 1 hour to make the pool back to original level
Answer:
What I would conclude when a random sample of 23 time intervals between eruptions has a larger mean longer than 108 minutes is that there must be an error that occurred somewhere while computing the result.
Step-by-step explanation:
Technically error can be explained as the estimated difference between the real value or calculated value and an observed value of a certain quantity.
basically we have three types of error which are;
1. systematic errors.
2.random errors.
3.Bluders.
BD bisects both the angles ABC and ADE
<u>Step-by-step explanation</u>:
IN ΔABD and ΔCBD ,
AD = CD [ given ]
BD = BD [ Common ]
AB = BC [ given ]
ΔABD ≅ ΔCBD [ SSS ]
∠ABD = ∠1
∠CBD = ∠2
∠1 =∠2 [ CPCT ] ( by using congruence theorem)
Also ,
∠3 = ∠4 [ CPCT ]
Hence, BD bisects both the angles ABC and ADE
