If Keith is represented by x, and Joe is three less than Keith, Troy is represented by x-3.
Then, we know that Joe exercises for twice the amount of time as Troy, we multiply the expression for Joe by two.
Keith = x
Troy = x-3
Joe = 2(x-3)
Answer:
Domain: {x | x is all real numbers} Range: {y | y ≥ 6}
Step-by-step explanation:
Domain is the set of all x values. No operations restrict the domain in this case. The domain is all real numbers.
Range is the set of all y values. Absolute value has a v shape starting at 0. Adding 6 raises this vertex to 6. The range is therefore all numbers greater than or equal to 6.
5 486 814 rounded to the nearest thousandth so here this is 6th digit:
because 7th digit is 4 we round down:
548.6814≈548,681
Answer:
g(x)=(x+7)^2-3
Step-by-step explanation:
Given:
f(x)= x^2
Now we have to translate f(x) 7 units to the left and 3 units down to form the function g(x).
As per the rules of translation
when any parent function, in given case f(x)=x^2, is translated to 'a' units to the left then 'a' is added to the value of x. thus making f(x+a)
Also when the parent function is translated any 'a' units down then 'a' is subtracted from the value of function. thus making f(x)-a
Translating f(x), 7 units to the left
f(x+7)= (x+7)^2
Translating f(x+7), 3 units down
f(x+7)-3 = (x+7)^2-3
Hence new function g(x)=(x+7)^2-3!
