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hram777 [196]
3 years ago
15

Jessica plans to spend no

Mathematics
1 answer:
bixtya [17]3 years ago
3 0

Answer:

Step-by-step explanation:

50 dollars 2 book bags

50 divided by 12 so you get 4

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A) x > -3

That's the answer

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Anyone care to help me with my math?
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A total of 31,000 is to be invested, some in bonds and some in certificates of deposit (CDs). If the amount invested in bonds is
kupik [55]

Answer:

Bonds: $42,000

Certificates of deposit: $41,000

Step-by-step explanation:

Total invested = Amount in bonds + Amount in CDs

 

Amount in bonds = Amount in CDs + 1000

 

Let the amount in bonds = B and the amount in CDs = C

 

 

1. 83,000 = B + C

 

2. B = C+1000

 

Since the above expression (#2) defines B, you can substitute it for the B in the first equation (#1).

 

83,000 = C + 1000 + C

 

Now, you can solve for C.

 

83,000 = 2C + 1000

82,000 = 2C

41,000 = C

 

You know that the amount invested in bonds is $1000 greater than the amount invested in CDs, so add $1000 to C and you find B, $42,000.

4 0
3 years ago
A principle of $2000 is placed ina saving account at 3% APR compounded annually. How much is in the account after one year, two
Kisachek [45]

Answer:

1 year:  $2060

2 years: $2121.80

3 years: $2185.45

Step-by-step explanation:

Compound interest formula is A = P(1 + \frac{r}{n}^{nt) where A is the final amount, P is the initial principal balance, r is the interest rate, n is the number of times interest applied per time period, and t is the number of time periods elapsed. In our case, P would be equal to 2000 dollars, r would be equal to 0.03, for 3 percent, and our n value would just be one, so the final equation is:

2000(1.03)^t

First, let's evaluate t for 1, as in one year.

2000 * 1.03^1 = 2000 x 1.03 = 2060

Two years: 2000 * 1.03 squared = 2121.80

Three years: 2000 * 1.03^3 = 2185.45!

Hope this helps!

8 0
2 years ago
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