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2 years ago

Describe what the graph of the sounds at a rock concert look like.

1 answer:

3 0

The graph would be similar to a Sin or Cos graph with a vertical shift. As the music gets louder the graph will go up and as the music and crowd become quieter, the graph will go down. Going up and down until the end of the concert where it will be 0.

Also side note, are you by chance in Trig 01 Summer course? If so, I am in the same class haha.

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PLZZZZZZZZZZ HELP ME WITH THIS

Pavlova-9 [17]

Answer:

First answer:

-16y=-19x+12

16y=19x-12

y=19/16x-3/4

Second answer:

8y=-15x-9

y=-15/8x-9/8

7 0

2 years ago

dion flips a coin 20 times and records if it comes up heads. if getting heads is a success, what is the probability of a success

kolbaska11 [484]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

The probability of success (getting heads) on one roll DOESNT affect other rolls, so we need to find probability of getting a head in a roll.

Probability is defined as the number of favorable outcomes divided by the total number of outcomes.

Here, favorable outcome is getting a head. So, on one roll, getting a head is 1. Also, the total number of outcomes is either a head or a tail. So total number of outcomes is 2.

Thus,

P(Heads) = 1/2

3 0

3 years ago

Identify the ordered pair on the graph of the equation 2x + 5y = 4.

Colt1911 [192]

What you would do is you would substitute each ordered pair into their respective variables. (ie. for (0,1) you would put 0 where the x is and 1 where the y is) You would then solve the equation. If the equation is not even (ie. 2=5 would not be even but 4=4 would be), you move on to the next ordered pair.

If you follow the process right and you get the equations correct, the answer should be B. (7,-2)

6 0

2 years ago

Is this a function graph

ELEN [110]

Yes it is a function graph

8 0

2 years ago

Listed below are the lead concentrations in mu ??g/g measured in different traditional medicines. Use a 0.10 0.10 significance l

laiz [17]

Answer:

We conclude that the mean lead concentration for all such medicines is less than 17 mu.

Step-by-step explanation:

We are given below are the lead concentrations in mu;

6.5 18.5 21.5 5.5 8.5 4.5 4.5 17.5 15.5 20

We have to test the claim that the mean lead concentration for all such medicines is less than 17 mu.

Let $\mu$ = mean lead concentration for all such medicines.

So, Null Hypothesis, $H_0$ : $\mu$ = 17 mu {means that mean lead concentration for all such medicines is equal to 17 mu}

Alternate Hypothesis, $H_A$ : $\mu$ < 17 mu {means that the mean lead concentration for all such medicines is less than 17 mu}

The test statistics that would be used here One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}$ ~ $t_n_-_1$

where, $\bar X$ = sample mean lead concentration = $\frac{\sum X}{n}$ = 12.25 mu

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 6.96 mu

n = sample size = 10

So, test statistics = $\frac{12.25 -17}{\frac{6.96}{\sqrt{10}}}$ ~ $t_9$

= -2.16

The value of t test statistics is -2.16.

Now, the P-value of the test statistics is given by the following formula;

P-value = P( $t_9$ < -2.16) = 0.031

Now, at 0.10 significance level the t table gives critical value of -1.383 for left-tailed test. Since our test statistics is less than the critical value of t as -2.16 < -1.383, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean lead concentration for all such medicines is less than 17 mu.

7 0

3 years ago