Ask question

Ask question

All categories

3 years ago

5

A bacyard gardener has calculated that she will need 425 square feet to grow the crops she wants. If her garden must be 25 feet

wide, how long will it need to be?

1 answer:

Nonamiya [84]3 years ago

3 0

Answer:

17 Feet

Step-by-step explanation:

Area = length * width

425 = x * 25

425/25 = x

x = 17

You might be interested in

Solve the equation.

Mekhanik [1.2K]

Answer:

3(x_1)=2(3_x)

or,3×_3 =6_2×

or,3×+2× =6+3

or,5× =9

or,× =9/5

4 0

3 years ago

Read 2 more answers

What’s all the answers to lesson 9 algebra 1 a unit 5

Lena [83]

Do you have a picture or some information of some sort?

8 0

4 years ago

Which expression represnts the product of 2xy and 3xy+5y-xy^2

melisa1 [442]

Answer:

You distribute the 2xy and get

2xy(3xy + 5y - xy^2) = 6(x^2)(y^2) + 10xy^2 - 2(x^2)(y^3)

8 0

3 years ago

EASY BRAINLIEST PLEASE HELP!!

butalik [34]

Answer:

see below

Step-by-step explanation:

<h3>Proposition:</h3>

Let the diagonals AC and BD of the Parallelogram ABCD intercept at E. It is required to prove AE=CE and DE=BE

<h3>Proof:</h3>

1)The lines AD and BC are parallel and AC their transversal therefore,

$\displaystyle \angle DAC = \angle ACB \\ \ \qquad [\text{ alternate angles theorem}]$

2)The lines AB and DC are parallel and BD their transversal therefore,

$\displaystyle \angle BD C= \angle ABD \\ \ \qquad [\text{ alternate angles theorem}]$

3)now in triangle ∆AEB and ∆CED

$\displaystyle \angle EAD=\angle ECB$
$\angle EDA=\angle EBC$
$\displaystyle AD=BC$

therefore,

$\displaystyle \Delta AEB \cong \Delta CED$

hence,

AE=CE
DE=BE

Proven

6 0

3 years ago

Given: ∆ABC, AB = BC, BM = MC<br> AC = 40, m∠BAC = 42º<br> Find: AM

Anna [14]

Answer:

The length of AM is 26.50 units.

Step-by-step explanation:

Given information: AB = BC, BM = MC , AC = 40, ∠BAC = 42º.

Since two sides of triangle are equal, therefore the triangle ABC is an isosceles triangle.

The corresponding angles of congruents sides are always equal. So angle C is 42º.

According to the angle sum property the sum of interior angles is 180º.

$\angle B=180-42-42=96$

Law of Sine

$\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}$

$\frac{\sinB}{AC}=\frac{\sin(C}{AB}$

$\frac{\sin(96)}{40}=\frac{\sin(42}{AB}$

$AB\sin(96)=40\sin(42)$

$AB=\frac{40\sin(42)}{\sin(96)}$

$AB=26.91$

Therefore the length of AB and BC is 26.91.

Since M is midpoint of BC, so

$BM=\frac{BC}{2}=\frac{26.91}{2}=13.455$

Use Law of Cosine in triangle ABM to find the value of AM.

$a^2=b^2+c^2-2bc\cos A$

$AM^2=AB^2+BM^2-2(AB)(BM)\cos (B)$

$AM^2=(26.91)^2+(13.455)^2-2(26.91)(13.455)\cos (96)$

$AM=26.50$

Therefore the length of AM is 26.50 units.

6 0

3 years ago