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eimsori [14]
3 years ago
7

Which statements can be represented by this equation? Select three options.

Mathematics
2 answers:
mars1129 [50]3 years ago
5 0

Answer:

Options A,C and E.

Step-by-step explanation:

The given equation is

2n-9.2=n+\dfrac{4}{5}

Let n be the unknown number, then

Twice a number minus nine and two-tenths is the same as the number plus four-fifths.

2n-9.2=n+\dfrac{4}{5}

So, option A is correct.

Nine point two decreased by double a number is the same as the number added to four-fifths.

9.2-2n=n+\dfrac{4}{5}

Nine point two less than twice a number is equal to the number added to four-fifths.

2n-9.2=n+\dfrac{4}{5}

So, option C is correct.

Two times the difference of a number and nine and two-tenths is equal to the number plus four-fifths.

2(n-9.2)=n+\dfrac{4}{5}

Double a number decreased by nine and two-tenths is the same as the sum of four-fifths and the number.

2n-9.2=n+\dfrac{4}{5}

So, option E is correct.

Therefore, the correct options are A,C and E.

Volgvan3 years ago
5 0

Answer:

<h3>A, C, and E</h3><h3>Step-by-step explanation: i did the quiz on Edg</h3>
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Find the area of each sector. Round your answers to the nearest tenth. ​
nata0808 [166]

Answer:

Area of sector = 102.6 feet squared

Step-by-step explanation:

Given:

Radius of circle = 14 ft

Angle θ = 60°

Find:

Area of sector

Computation:

Area of sector = [θ/360]πr²

Area of sector = [60/360](22/7)(14)²

Area of sector = [1/6][22/7][196]

Area of sector = 102.6 feet squared

3 0
3 years ago
What is the interval when written in the form of (lower limit, upper limit)(lower limit, upper limit) ?
Stels [109]
The interval <span>when written in the form of lower limit and the upper limit would be 95.8 - 98.2. This can be calculated by subtracting 95 with 1.2 and by adding 95 with 1.2. Hope this answers the question. Have a nice day. Feel free to ask more question.</span>
8 0
4 years ago
Triangle ABC has vertices at A(2,3),B(-4,-3) and C(2,-3) find the coordinates of each point of concurrency.
dem82 [27]

Answer:

Circumcenter =(-1,0)

Orthocenter =(2,-3)

Step-by-step explanation:  

Given : Points A = (2,3), B = (-4,-3), C = (2,-3)  

Formula used :  

→Mid point of two points- (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

→Slope of two points - \frac{y_2-y_1}{x_2-x_1})

→Perpendicular of a line = \frac{-1}{slope of line})

Circumcenter- The point where the perpendicular bisectors of a triangle meets.

Orthocenter-The intersecting point for all the altitudes of the triangle.

To find out the circumcenter we have to solve any two bisector equations.

We solve for line AB and AC

So, mid point of AB =(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)

Slope of AB =\frac{-3-3}{-4-2}=1

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of the perpendicular bisector = -1  

Equation of AB with slope -1 and the coordinates (-1,0) is,  

(y – 0) = -1(x – (-1))  

y+x=-1………………(1)  

Similarly, for AC  

Mid point of AC = (\frac{2+2}{2},\frac{3-3}{2})=(2,0)

Slope of AC = \frac{-3-3}{2-2}=\frac{-6}{0}  

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of the perpendicular bisector = 0  

Equation of AC with slope 0 and the coordinates (2,0) is,  

(y – 0) = 0(x – 2)  

y=0 ………………(2)  

By solving equation (1) and (2),  

put y=0 in equation (1)

y+x=-1

0+x=-1

⇒x=-1  

So the circumcenter(P)= (-1,0)

To find the orthocenter we solve the intersections of altitudes.

We solve for line AB and BC

So, mid point of AB =(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)

Slope of AB =\frac{-3-3}{-4-2}=1

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of CF = -1  

Equation of AB with slope -1 and the coordinates (-1,0) gives equation CF  

(y – 0) = -1(x – (-1))  

y+x=-1………………(3)  

Similarly, mid point of BC =(\frac{-4+2}{2},\frac{-3-3}{2})=(-1,-3)

Slope of AB =\frac{-3+3}{-4-2}=0

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of AD = 0

Equation of AB with slope 0 and the coordinates (-1,-3) gives equation AD

(y-(-3)) = 0(x – (-1))  

y+3=0

y=-3………………(4)  

Solve equation (3) and (4),

Put y=-3 in equation (3)

y+x=-1

-3+x=-1

x=2

Therefore, orthocenter(O)= (2,-3)


7 0
3 years ago
A rectangle sand box has a length of 5 and 1/3 feet and a width of 3 and 3/4 feet. What is the perimeter?
Varvara68 [4.7K]

Answer:

Perimeter of rectangle = ⇒ 18\frac{1}{6} feet

Step-by-step explanation:

Given:

Length of a rectangular sand box = 5\frac{1}{3}\ feet

Width of the box = 3\frac{3}{4}\ feet

Perimeter of a rectangle = 2(l+w)

where l represents length of rectangle and w represents width of the rectangle.

Substituting values given for length and width.

Perimeter of sand box = 2(5\frac{1}{3}+3\frac{3}{4})\ feet

Simplifying by adding fractions:

⇒  2(5+3+\frac{1}{3}+\frac{3}{4})\ feet (Adding whole numbers and fractions separately)

⇒  2(8+\frac{1}{3}+\frac{3}{4}) feet

Whole number 8 can be written as \frac{8}{1}

⇒  2(\frac{8}{1}+\frac{1}{3}+\frac{3}{4}) feet

To add fractions we take LCD for the denominators 3,4,1.

LCD for 3 and 4 = 12 as its the least common multiple of 3,4,1.

Making denominators =12 by multiplying numerator an denominator with the corresponding numbers

⇒  2(\frac{8\times 12}{1\times 12}+\frac{1\times 4}{3\times 4}+\frac{3\times 3}{4\times 3}) feet

⇒  2(\frac{96}{12}+\frac{4}{12}+\frac{9}{12}) feet

Then we simply add numerators.

⇒  2(\frac{96+4+9}{12}) feet

⇒  2(\frac{109}{12}) feet

⇒  2\times \frac{109}{12} feet

⇒  \frac{218}{12} feet

Writing fraction as a mixed number by dividing 218 by 12 and writing quotient as whole number and remainder as numerator with divisor as denominator.

⇒ 18\frac{2}{12} feet

Simplifying fractions to simplest form.

⇒ 18\frac{1}{6} feet

Perimeter =⇒ 18\frac{1}{6} feet  (Answer)

5 0
3 years ago
Lilly has 38 baseballs. She places all the baseballs into one or more containers. Lilly places the same number of baseballs into
Dvinal [7]

Answer:

There are 4 possible ways to place the baseballs into containers.

Step-by-step explanation:

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7 0
2 years ago
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