The answer is b because it shows
If A is QIV, then 3π/2 ≤A≤2π;
we have to find out in what quadrant is A/2
(3π/2)/2≤A/2≤(2π)/2 ⇒ 3π/4≤A/2≤π
We can see that A/2 will be in QIII; therefore the sec (A/2) will be negative (-).
1) we have to calculate cos (A/2)
Cos (A/2)=⁺₋√[(1+cos A/2)/2]
We choose this formula: Cos (A/2)= -√[(1+cos A/2)/2], because sec A/2 is in quadrant Q III, and the secant (sec A/2=1/cos A/2) in this quadrant is negative.
Cos (A/2)=-√[(1+cos A)/2]=-√[(1+(1/2)]/2=-√(3/4)=-(√3)/2.
2) we compute the sec (A/2)
Data:
cos (A/2)=-(√3)/2
sec (A/2)=1/cos (A/2)
sec (A/2)=1/(-(√3)/2)=-2/√3=-(2√3)/3
Answer: sec (A/2)=-(2√3)/3
Answer:
The equation of the axis of symmetry for this parabola is x = 0.
Step-by-step explanation:
For parabola's, it's axis of symmetry always goes through the vertex of the parabola. In other words, the axis of symmetry is vertical line that goes through the x-coordinate of the vertex.
Now, the vertex is given as (0,3) which is at x = 0, y = 3.
Thus, the vertical line that goes through the x-coordinate of the vertex will be x = 0
Thus, the equation of the axis of symmetry for this parabola is x = 0.
<u>These 2 equations has </u><u>no solution</u><u> and the equations are </u><u>independent</u><u> </u><u>of each other.</u>
What is liner equation with two variable?
- An equation is said to be linear equation in two variables if it is written in the form of ax + by + c=0, where a, b & c are real numbers and the coefficients of x and y, i.e a and b respectively, are not equal to zero.
- For example, 10x+4y = 3 and -x+5y = 2 are linear equations in two variables.
-10x² -10y² = -300 ----a
5x² + 5y² = 150 ---- b
While trying to solve this,
We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.
10x² + 10y² = 300 ----c
-10x² -10y² = -300 ---a
<u>Everything cutoff, we will </u><u>get 0</u><u>, and there is no solution to these equations.</u>
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Answer:
3%
Step-by-step explanation:
I = Prt
I = 1020
P = 8500
t = 4
1020 = (8500)(4)r
1020 = 34000r
r = 0.03