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Masteriza [31]
3 years ago
15

How to do this question?

Mathematics
1 answer:
diamong [38]3 years ago
3 0

Remark

Drawing that diagram was a very good idea. If you can picture something happening, you are half way there. I tend to use a table, but the diagram will come to the same thing.

                  Olivia                    Dawn

Start            176                         80

<u>Donate         x                             x      Subtract</u>

What's left   176 - x                  80 - x

Equation

176 - x = 5*(80 - x)     Olivia had 5 times as many books as Dawn did.   Remove the brackets.      

Solution

176 - x = 400 - 5x                 Add 5x to both sides

176 + 5x - x = 400                  Combine terms on the left

176 + 4x = 400                    Subtract 176 from both sides

4x = 400 - 176                     Combine terms on the right.

4x = 224                              Divide by 4

x = 224/4    

x = 56                                 Answer

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Answer: 264

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The volume of a cylinder with height h h and radius r r can be found using the formula V = ? r 2 h V=?r2h Find the volume of a c
Pavel [41]

Answer:

5.000 ft

Step-by-step explanation:

The formula for the volume of a cylinder is

V = πr²h

Data:

V = 785.4 ft³

h = 2r

Calculations:

V = πr²h = πr²(2r) = 2πr³

Divide each side by 2π

\frac{V }{2\pi } = r^{3}  

Take the cube root of each side

r = \sqrt[3]{\frac{V }{2\pi}}

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6 0
3 years ago
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Step-by-step explanation:

5 0
3 years ago
Ginny's piggybank contained $8.80 in quarters, dimes, and nickels. there were two more than five times as many nickels as quarte
SSSSS [86.1K]

Answer:

There are 13 quarters, 67 nickels, and 22 dimes.


Step-by-step explanation:

The value of a quarter is $0.25, the value of dime is $0.10, and the value of a nickel is $0.05. Let there be q quarters, n nickels, and d dimes.

Let's write equations from the statements given:


<u>"Ginny's piggybank contained $8.80 in quarters, dimes, and nickels.":</u>

0.25q+0.1d+0.05n=8.80

<u>"there were two more than five times as many nickels as quarters":</u>

5q+2=n

<u>"4 less than twice as many dimes as quarters":</u>

<u>2q-4=d</u>


Plugging in equation 2 and 3 into equation 1, we can solve for q:

0.25q+0.1(2q-4)+0.05(5q+2)=8.80\\0.25q+0.2q-0.4+0.25q+0.1=8.80\\0.7q=8.80+0.4-0.1\\0.7q=9.1\\q=\frac{9.1}{0.7}=13

<em>Substituting q = 13 into equation 2 will give us nickels:</em>

n=5q+2\\n=5(13)+2\\n=67

<em>Substituting q = 13 into equation 3 will give us dimes:</em>

d=2q-4\\d=2(13)-4\\d=22


There are 13 quarters, 67 nickels, and 22 dimes.

4 0
3 years ago
Find the volume. Confusing
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