Answer:
d. The trigger is fired more than once.
Explanation:
What would happen in this situation is that the trigger would be fired more than once. This is because the trigger will be fired when the user updates the record. It will also be fired when the process builder is run.
If the trigger fires more than once, this can be problematic for the developer. Therefore, it is better if the trigger fires just once, as this is the time when the present changes can be placed.
Answer:
The code has been written in Java.
The source code of the file has been attached to this response. The source code contains comments explaining important lines of the program.
A sample output got from a run of the application has also been attached.
To interact with the program, kindly copy the code into your Java IDE and save as Cafe.java and then run the program.
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
java
</span>
Answer:
Following is given the detailed solution of the given question.
I hope it will help you!
Explanation:
Answer:
- def getData(a_dict, key_list):
- result = []
-
- for key in key_list:
- result.append(a_dict[key])
-
- return result
-
- result = getData( {"puffin": 5, "corgi": 2, "three": 3} , ["three", "corgi"])
- print(result)
Explanation:
Let's define a function <em>getData() </em>with two parameters,<em> a_dict </em>and <em>key_list</em> as required by the question (Line 1).
Since the function is to return a list of associated values of dictionaries, a new list,<em> result</em>, is declared and initialized with empty values (Line 2).
Next, use for-loop to traverse through every string in the input <em>key_list </em>(Line 4) and use the traversed key to address the value in the<em> a_dict </em>and add it to the <em>result</em> list (Line 5)
At last, return the <em>result </em>list as output (Line 7)
We can test the function using the test case from the question and we shall see the output as follows:
[3, 2]
Try to untangle them, First!
Then the color of the wire must match the color hole it goes in (I’m guessing)
I’m not good with electronics so sorry.