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Semenov [28]
3 years ago
12

careful driving requires the appropriate Reaction Time both simple and complex breaking and then shifting gears followed by sign

aling and then hitting the horn are examples of what _?__ reaction time and are usually required in most driving situations
Computers and Technology
1 answer:
arlik [135]3 years ago
6 0

The examples listed all belong in the category of complex reaction time.

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What are the different types database of end users? Discuss the main activi-ties of each
disa [49]

Answer:

following types of databases available in the market −

Centralised database.

Distributed database.

Personal database.

End-user database.

Commercial database.

NoSQL database.

Operational database.

Relational database.

Cloud database.

Object-oriented database.

Graph database

8 0
3 years ago
Read 2 more answers
Why are high-quality transformers wound with large diameter wire?
lesya692 [45]
So that they can lower the I2R losses
8 0
4 years ago
You can access decorative underlines and change their color through the ____ drop-down.
Dominik [7]
The answer is "underline gallery or underline drop-down". The user can access the decorative underlines and change the underline's color through the underline gallery. Underlines can be added for decoration purposes, to make your work look formal or creative.
4 0
3 years ago
Which pattern is produced by the following code? for (int i = 1; i <= 6; i++) { for (int j = 6; j >= 1; j--) System.out.pr
Brrunno [24]

Answer:

              1                                                                                                                    

           2 1                                                                                                                    

        3 2 1                                                                                                                    

     4 3 2 1                                                                                                                    

  5 4 3 2 1                                                                                                                    

6 5 4 3 2 1

Explanation:

I do not now know which option it corresponds but the shape should look like above.

The logic is following;

There is a nested for loop. The inner loop prints the value of j, when j is smaller than or equal to i. Otherwise, it prints a space.

For example, in the first iteration i = 1 and j starts from 6.

i = 1, j = 6 -> print space

i = 1, j = 5 -> print space

i = 1, j = 4 -> print space

i = 1, j = 3 -> print space

i = 1, j = 2 -> print space

<u>i = 1, j = 1 -> print j</u>

3 0
3 years ago
Write the definition of a function named quadratic that receives three double parameters a, b, c. If the value of a is 0 then th
VMariaS [17]

Answer:

#include <iostream>

#include <cmath>

using namespace std;

//initialize function quadratic

void quadratic(double, double, double);

int main() {

   //declare double variables a, b and c

   double a,b,c;

   //take input from user

   cin>>a>>b>>c;

   //call function quadratic

   quadratic(a,b,c);

return 0;

}

void quadratic(double a, double b, double  c){

   double root,n;

   //check if variable a is equal to zero

   if(a==0){

       cout<<"no solution for a=0"<<endl;

       return;

   }

   //check if b squared - 4ac is less than zero

   else

   if(((b*b)-(4*a*c))<0){

       cout<<"no real solutions"<<endl;

       return;

   }

   //print the largest root if the above conditions are not satisfied

   else{

       n=((b*b)-(4*a*c));

       root=(-b + sqrt(n)) / (2*a);

       cout<<"Largest root is:"<<root<<endl;

   }

   return ;

}

Explanation:

Read three double variables a, b and c from the user and pass it to the function quadratic. Check if the value of variable a is equal to zero. If true, print "no solution for a=0". If this condition is false, check if b squared - 4ac is less than zero. If true, print "no real solutions". If this condition is also false, calculate the largest solution using the following formula:

largest root = (-b + square root of (b squared - 4ac)) / (2*a)

Input 1:

2 5 3

Output 2:

Largest root is:-1

Input 2:

5 6 1

Output 2:

Largest root is:-0.2

5 0
4 years ago
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