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weeeeeb [17]
3 years ago
8

You can access decorative underlines and change their color through the ____ drop-down.

Computers and Technology
1 answer:
Dominik [7]3 years ago
4 0
The answer is "underline gallery or underline drop-down". The user can access the decorative underlines and change the underline's color through the underline gallery. Underlines can be added for decoration purposes, to make your work look formal or creative.
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A person who has a been exposed to technology at a young age is?
Dahasolnce [82]
Ok if lets say a young child at the age of like 6-7 was allowed to play grand theft auto by his/her parents maybe the child would understand incorrectly and start doing what the people do in the game this may cause to serious trouble jail time or even death. In this case dont let your kids play underrated games or watch underrated movies.
Hope that helped you understand more.
7 0
3 years ago
Hi, please help me, solution.​
loris [4]

Answer:

error: incompatible types

Explanation:

Given

The attached code

Required

The output

Variable "a" is declared as float

While p is declared as a pointer to an integer variable

An error of incompatible types will be returned on line 3, <em>int *p = a;</em>

Because the variables are not the same.

To assign a to p*, we have to use type casting.

Hence, (b) is correct

5 0
3 years ago
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
3 years ago
Chang investigates ways to improve the interactivity of computer hardware. His job title is best described as ✓ Computer and Inf
xeze [42]

Answer:

B, D, C

Explanation:

got it right

3 0
2 years ago
Part1) Given 3 integers, output their average and their product, using integer arithmetic.
Mrac [35]

Answer:

The program is as follows:

#include <iostream>

#include <iomanip>

using namespace std;

int main(){

   int num1, num2, num3;

   cin>>num1>>num2>>num3;

   cout << fixed << setprecision(2);

   cout<<(num1 + num2 + num3)/3<<" ";

   cout<<num1 * num2 * num3<<" ";

   return 0;

}

Explanation:

This declares three integer variables

   int num1, num2, num3;

This gets input for the three integers

   cin>>num1>>num2>>num3;

This is used to set the precision to 2

   cout << fixed << setprecision(2);

This prints the average

   cout<<(num1 + num2 + num3)/3<<" ";

This prints the product

   cout<<num1 * num2 * num3<<" ";

6 0
3 years ago
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