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3 years ago

Find the range of the following piecewise function. [2,16) (2,16] [2,∞) (2,∞)

Mathematics

2 answers:

Svet_ta [14]3 years ago

8 0

Answer:

Step-by-step explanation:

Find the range of the following piecewise function.

[2,16)

(2,16]

[2,∞)

(2,∞)

12345 [234]3 years ago

7 0

Range is the set of possible values of y in the ordered pairs.

the piecewise function has possible values
2, 7+ to 11- and 16 to ∞
which can be written as
{2 ∪ (7,11) ∪ [16,∞)}
in interval notation.

I think the answer choices you posted correspond to another problem.

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Which quadrilateral makes this statement true?<br><br><br>Quadrilateral ABCD ≅ _____

leva [86]

Answer:

Step-by-step explanation:

They are literally the same quadrilateral. Same side lengths and angle measures.

6 0

2 years ago

Bet u can’t solve this

S_A_V [24]

Answer:

Step-by-step explanation:

Assuming you're solving for p:

$m=2^{-1} *2^p(2^p-1)$

Let $y=2^p$

Now we can re-write the equation with $y$ instead of $2^p$ .

$m=\frac{1}{2} y(y-1)$

$2m=y^2-y$

$y^2-y-2m=0$

Use the quadratic formula to get:

$y = \frac{1+\sqrt{1+8m} }{2}$

$y = \frac{1-\sqrt{1+8m} }{2}$

Therefore, using natural log and log rules:

$2^p = \frac{1+\sqrt{1+8m} }{2}$ , $ln(2^p)= ln(\frac{1+\sqrt{1+8m} }{2})$ , $pln(2) = ln(\frac{1+\sqrt{1+8m} }{2})$ , $p = \frac{ln(\frac{1+\sqrt{1+8m} }{2})}{ln(2)}$

$2^p = \frac{1-\sqrt{1+8m} }{2}$ , $ln(2^p)= ln(\frac{1-\sqrt{1+8m} }{2})$ , $pln(2) = ln(\frac{1-\sqrt{1+8m} }{2})$ , $p = \frac{ln(\frac{1-\sqrt{1+8m} }{2})}{ln(2)}$

If I haven't made any mistakes this should be correct!

7 0

3 years ago

10) Solve the problem below using any method. Define your variables and write out the two

irga5000 [103]

Answer:

Variables: r, s

Number of Regular Tickets: 215

Equations: 8r + 6s = 3580; r + s = 525

Number of Senior Tickets: 310

Step-by-step explanation:

10) Solve the problem below using any method. Define your variables and write out the two equations. Then solve the problem.

A movie theater sells regular tickets for $8.00 and senior tickets for $6.00. One evening the theater

sold 525 tickets and took in $3580 in revenue. How many of each type of ticket were sold?

let r = number of regular tickets

let s = number of senior tickets

Equations:

The first equation deals with money.

8r + 6s = 3580

The second equation deals with numbers of tickets.

r + s = 525

Use the substitution method.

Solve the second equation for r.

r + s = 525

r = 525 - s

Substitute 525 - s for r in the first equation.

8r + 6s = 3580

8(525 - s) + 6s = 3580

4200 - 8s + 6s = 3580

4200 - 2s = 3580

-2s = -620

s = 310

Now substitute 310 for s in the equation r = 525 - s

r = 525 - 310

r = 215

Variables: r, s

Number of Regular Tickets: 215

Equations: 8r + 6s = 3580; r + s = 525

Number of Senior Tickets: 310

7 0

2 years ago

Solve the radical equation. square root 6n-11= n – 3 Which solution is extraneous? A.)2

Anvisha [2.4K]

ANSWER

D) 10

EXPLANATION

We want to solve the radical equation,

$\sqrt{6n - 11} = n - 3$

Square both sides,

$6n - 11 = (n - 3) ^{2}$

Expand brackets on right hand side,

$6n - 11 = {n}^{2} - 6n + 9$

Rewrite in general quadratic equation form,

${n}^{2} - 12n + 20 = 0$

Factor to obtain,

$(n - 2)(n - 10) = 0$

Apply the zero product principle to get,

$n = 2 \: or \: n = 10$

We put n=2 into the equation to get,

$\sqrt{6(2) - 11} = 2 - 3$

$1 = - 1$

This statement is false, hence 2 is an extraneous solution

We put n=10, to get

$\sqrt{6(10) - 11} = 10 - 3$

$\sqrt{49} = 7$

$7 = 7$

This is true, hence the only solution is
$n = 10$

3 0

4 years ago

Read 2 more answers

Need help my teacher is going to be really mad

neonofarm [45]

This is how I figure these type of questions out you can draw a circle on the J,K,L the trace it to make a triangle it should be less then 90 degrees if not then you might’ve traced it wrong.

5 0

4 years ago