Evaluate k(t) = 13t-2 k(3)=

In a sample of nequals16 lichen specimens, the researchers found the mean and standard deviation of the amount of the radioacti

Dovator [93]

Answer:

(a) The confidence level desired by the researchers is 95%.

(b) The sampling error is 0.001 microcurie per millilitre.

(c) The sample size necessary to obtain the desired estimate is 36.

Step-by-step explanation:

The mean and standard deviation of the amount of the radioactive element, cesium-137 present in a sample of n = 16 lichen specimen are:

$\bar x=0.009\\s=0.003$

Now it is provided that the researchers want to increase the sample size in order to estimate the mean μ to within 0.001 microcurie per millilitre of its true value, using a 95% confidence interval.

The (1 - α)% confidence interval for population mean (μ) is:

$CI=\bar x \pm z_{\alpha/2}\times \frac{s}{\sqrt{n}}$

(a)

The confidence level is the probability that a particular value of the parameter under study falls within a specific interval of values.

In this case the researches wants to estimate the mean using the 95% confidence interval.

Thus, the confidence level desired by the researchers is 95%.

(b)

In case of statistical analysis, during the computation of a certain statistic, to estimate the value of the parameter under study, certain error occurs which are known as the sampling error.

In case of the estimate of parameter using a confidence interval the sampling error is known as the margin of error.

In this case the margin of error is 0.001 microcurie per millilitre.

(c)

The margin of error is computed using the formula:

$MOE=z_{\alpha/2}\times \frac{s}{\sqrt{n}}$

The critical value of z for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the sample size value as follows:

$MOE=z_{\alpha/2}\times \frac{s}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times s}{MOE}]^{2}$

$=[\frac{1.96\times 0.003}{0.001}]^{2}$

$=34.5744\\\approx36$

Thus, the sample size necessary to obtain the desired estimate is 36.

8 0

3 years ago

Whats 92 divided by 2.7

Stells [14]

Answer:

34.074

Step-by-step explanation:

7 0

3 years ago

The vertices of angleABC are A(1,1) B(5,1) C(3,3) drawl the triangle and it’s image A’B’C’ reflected in the Y axis. What are the

nevsk [136]

For any point reflected in the y- axis

(x, y ) → (- x, y )

A(1, 1) → A'(- 1, 1)

B(5, 1 ) → B'(- 5, 1 )

C(3, 3 ) → C'(- 3, 3 )

6 0

3 years ago

A cooking club has 12 members. how many ways can they select a president and vice president from among the members? A.66 B. 132

emmasim [6.3K]

There are 10 possible ways to select a president from the club, because their are 10 available members to choose from.

After a president is chosen, their are 9 possible ways to select a vice president, because one of the members will already have the position of president, so they can't be vice president (10-1=9)

Now we just multiply to possibilities of presidents by the possibilities of vice-presidents.

president*vicepresident=
10*9=90

Answer= D. 90

6 0

4 years ago

Read 2 more answers

What is the birthday polynomial for 10/1/2006

zubka84 [21]

Answer:

Simplified version: 10x^5 - 1x^4 + 2x^3 - 6

Step-by-step explanation:

Since your birthday is 10/1/2006 we can use 1012006 as our digits.

We can make a random polynomial: 10x^5 - 1x^4 + 2x^3 + 0 x^2 + 0x - 6

(since 0 are meaningless we can simply this further into the below equation)

10x^5 - 1x^4 + 2x^3 - 6

Here's an example: https://www.wyzant.com/resources/answers/730225/birthday-polynomial-project-for-04-15-2004

8 0

2 years ago