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vredina [299]
3 years ago
5

help with this pick one of the 3 equations at the top then answer the questions about the one you pick giving 98 points

Mathematics
2 answers:
Rainbow [258]3 years ago
7 0
The equation I picked was x^2+5x-6=3

1. the parabola opens up as the leading coefficient is a positive.

2. to find the vertex to find the x value
-5/2(1)= -5/2 (-2 1/2) (-2.5)
to find the y value of the vertex substitie the x value into the equation
(-2 1/2)^2+5(-2 1/2)-6=3
6 1/4 - 12 1/2 -9 = y
-15 1/4 = y
y = -15 1/4 (-15.25)

(-2.5, 15.25) , (-2 1/2, -15 1/4)

3. the y intercept can be found by substituting the X's with 0's
x^2+5x-6=3
first move the terms to the left
x^2+5x-9=y
(0)^2+5(0)-9=y
0+9=y
9=y
y=9

the y intercept is 9 (0,9)

4. b^2-4ac
5^2-4(1)(-9)
=25+36
=61
61 is greater than 0 so this means there are 2 real solutions.

5.
x =    \frac{  - 5 +  - \sqrt{5^{2} - 4(1)( - 9) } }{2(1)}
x - =  \frac{ - 5 +  -  \sqrt{61} }{2}
x =   \frac{ - 5 +  \sqrt{61} }{2}  \: or \: x =  \frac{ - 5 +  \sqrt{61} }{2}
the +- next to each other is meant to be plus or minus

6. to find three other points pick any x value and substitute that into the equation

y=(2)^2+5(2)-9
y=4+10-9
y=5

(2,5)

y=(3)^2+5(3)-9
y=9+15-9
y=15

(3,15)

y=(4)^2+5(4)-9
y=16+20-9
y=27

(4,27)

I hope this helps, brainliest?
ehidna [41]3 years ago
4 0

Answer:

<em>x^2+5x-6=3</em>

<em />

<em>1. the parabola opens up as the leading coefficient is a positive.</em>

<em />

<em>2. to find the vertex to find the x value</em>

<em>-5/2(1)= -5/2 (-2 1/2) (-2.5)</em>

<em>to find the y value of the vertex substitie the x value into the equation</em>

<em>(-2 1/2)^2+5(-2 1/2)-6=3</em>

<em>6 1/4 - 12 1/2 -9 = y</em>

<em>-15 1/4 = y</em>

<em>y = -15 1/4 (-15.25)</em>

<em />

<em>(-2.5, 15.25) , (-2 1/2, -15 1/4)</em>

<em />

<em>3. the y intercept can be found by substituting the X's with 0's</em>

<em>x^2+5x-6=3</em>

<em>first move the terms to the left</em>

<em>x^2+5x-9=y</em>

<em>(0)^2+5(0)-9=y</em>

<em>0+9=y</em>

<em>9=y</em>

<em>y=9</em>

<em />

<em>the y intercept is 9 (0,9)</em>

<em />

<em>4. b^2-4ac</em>

<em>5^2-4(1)(-9)</em>

<em>=25+36</em>

<em>=61</em>

<em>61 is greater than 0 so this means there are 2 real solutions.</em>

<em>the +- next to each other is meant to be plus or minus </em>

<em />

<em>6. to find three other points pick any x value and substitute that into the equation</em>

<em />

<em>y=(2)^2+5(2)-9</em>

<em>y=4+10-9</em>

<em>y=5</em>

<em />

<em>(2,5)</em>

<em />

<em>y=(3)^2+5(3)-9</em>

<em>y=9+15-9</em>

<em>y=15</em>

<em />

<em>(3,15)</em>

<em />

<em>y=(4)^2+5(4)-9</em>

<em>y=16+20-9</em>

<em>y=27</em>

<em />

<em>(4,27)</em>

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