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Elenna [48]
3 years ago
14

Write an inequality for each graph.

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0

x = unknown number (that is a solution/makes the inequality true)

When the inequality sign is </> (less than/greater than), the dot is an open circle.

When the inequality sign is ≤/≥ (less than or equal to/greater than or equal to), the dot is a closed circle.

14.) The line has an open circle on -8, and a closed circle on 11.

-8 < x ≤ 11   [x is any number greater than -8 and less than or equal to 11]

15.) The line has a closed circle on -14 and 5.

-14 ≤ x ≤ 5    [x is any number greater than or equal to -14 and less than or equal to 5]

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What is the factorization of the polynomial below
Leya [2.2K]

Hello from MrBillDoesMath!

Answer:  Choice B, 2(x+7)(x+7)

Discussion:

For 2 out of each term in the polynomial:

2x^2+28x+98 =

2( x^2 + 14x + 49).

Note the 14 = 7 + 7 and 49 = 7*7 sp the polynomial factors as

2 (x+7)^2

which is choice B.


Thank you,

MrB


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7-3 Multiplying Binomials
Nataly [62]

Answer:

Step-by-step explanation:

Use FOIL method.First multiply (5x + 1) and (3x - 4). Then multiply (15x² - 17x - 4) by (x +2)

Volume of the rectangular prism = length *width * height

              = (5x + 1) (3x -4)(x +2)

              = [ 5x*3x + 5x*(-4)  + 1*3x + 1*(-4) ] (x + 2)

             = [15x² <u>- 20x + 3x</u> - 4] (x +2)    {Combine like terms}

             = [15x² - 17x - 4] (x + 2)

             =[15x² -17x - 4]*(x) + [15x² - 17x  -4]*2

            = [15x²*x - 17x*x - 4*x ]+ 15x²*2 - 17x *2  - 4*2

            = 15x³ - 17x² - 4x  + 30x² - 34x - 8

           = 15x³ <u>- 17x² + 30x²</u>  <u>- 4x - 34x </u>- 8    {Combine like terms}

           = 15x³ + 13x²  - 38x - 8

7 0
3 years ago
Solve to find missing length
shutvik [7]

Answer:

m = 4\sqrt 3\\n = 6

Step-by-step explanation:

\tan \: 60 \degree =  \frac{n}{2 \sqrt{3} }  \\  \\  \sqrt{3}  = \frac{n}{2 \sqrt{3} }   \\  \\ n =  \sqrt{3}  \times 2 \sqrt{3}  \\  \\ n = 2 \times 3 \\  \\ \huge \red { \boxed{ n = 6}} \\  \\  \cos \: 60 \degree =  \frac{2 \sqrt{3} }{m}  \\  \\  \frac{1}{2}  = \frac{2 \sqrt{3} }{m}   \\  \\ m = 2 \times 2 \sqrt{3}  \\  \\ \huge \purple{ \boxed{ m = 4\sqrt{3} }}

6 0
3 years ago
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