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Alona [7]
3 years ago
11

If the ratio of surface areas of 2 similar figures is 144/25 ; What is the ratio of their volumes?

Mathematics
1 answer:
kkurt [141]3 years ago
7 0

Answer:

1728/ 125

Step-by-step explanation:

The ratio of corresponding lengths  of the figures = ratio of the square root of their areas.

So ratio of lengths =  12/5.

Now volume is 3 dimensional  so the ratio is the cube  of the lengths

= 12^3/5^3

= 1728/ 125.

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Simplify this expression. 67 ÷ 65
TEA [102]

Answer:

it should be 67/65 or if in mixed number form :  1  2/65

6 0
3 years ago
Read 2 more answers
What is the variance of the data set? 8, 9, 10, 16, 17
adoni [48]
Mean = (8 + 9 + 10 + 16 + 17) / 5 = 60/5 = 12.

x - mean:

8 - 12 = -4,  -4² = 16

<span>9 - 12 = -3,  -3² = 9
</span>
<span>10 - 12 = -2,  -2² = 4
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<span>16- 12 = 4,  4² = 16</span>

<span>17- 12 = -5,  -5² = 25
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Sum of the squares =   16 + 9 + 4 + 16 +25 = 70

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6 0
2 years ago
Solve the the equation 3x2-3x+7
Alisiya [41]
3.2-3x+7
6-3x+7
-7    -7
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3 0
3 years ago
Help me pls due tmrw
stiv31 [10]

( a )pairs of vertical angles :

AGB and EGD

Vertical angles are a pair of opposite angles formed by intersecting lines. Vertical angles are equal in magnitude.

( b ) a pair of adjacent angles :

AGB and BGC

Adjacent angles are two angles that have a common side and a common vertex (corner point) but do not overlap in any way.

(c) Name a pair if supplementary angles :

AGB and BGD

Two angles are called supplementary when their measures add up to 180 degrees.

(d) A pair of complementary angles :

AGF and FGE

Two angles are called complementary when their measures add to 90 degrees.

(e) Find measure of CGD :

( look into the photo attached for better understanding)

CGD = 55°

<em>hope this helps :)</em>

8 0
2 years ago
Pls answer quick I will give bainlyest to first GOOD answer
Helen [10]

Answer:

R1 - given

R2 - subtraction property of equality

R3 - distribution

S4 - 9x = 61

R5 - division prop. of equality

Step-by-step explanation:

hope this helps :)

5 0
3 years ago
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