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MatroZZZ [7]
3 years ago
5

Enter the missing value into the box to complete the ratio comparing 75 centimeters to 3 meters. 1 to

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
5 0
The ratio for the problem above is one to four. A ratio is a relationship between number which describes how many times the second number contains the first number. The problem above gave two metric unit of length which are the centimeter and meter and the ratio between those two is one to a hundred. Therefore, we have a comparison between two amounts which are 75 and 300 and we can conclude a ratio of one to four.
amm18123 years ago
3 0
I have the same thing in my semester quiz how ironic but it is 0.4 because when you divide 75 centimeters to 3 you end up getting 25 or 0.4 than you subtract it it down drop 25 and you get 0.4
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3 years ago
Which of the following points are more than 5 units from the point P(−2, −2)? Select all that apply. A A (2, 1) B B (4, −1) C C
netineya [11]

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

<span> |PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}</span></span>


Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.


|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5

|PB|= \sqrt{ (-2-4)^{2} + (-2+1)^{2}}= \sqrt{36+1}= \sqrt{37} \approx 6

|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4

|PD|= \sqrt{ (-2+6)^{2} + (-2+6)^{2}}= \sqrt{16+16}= \sqrt{32}\ \textgreater \  \sqrt{25}=5

|PE|= \sqrt{ (-2+5)^{2} + (-2-1)^{2}}= \sqrt{9+9}= \sqrt{16}=4


Answer: B and D





3 0
3 years ago
a $35 decrease followed by a $25 increase is it same as the origional price,is it less the the origional ,or is it greater than
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3 years ago
What does 5.74 round to
kodGreya [7K]
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The nearest tenth rounds to 5.70

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3 years ago
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