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2 years ago

8

Help me with this please, anyone?

2 answers:

frutty [35]2 years ago

8 0

i DON;T KNOW MAYBE 10+9=21 is the correct answer. let me know if it right! hope u have a grate day

saveliy_v [14]2 years ago

8 0

the last statement is true, that is

the table represents a function because each input has exactly one output assigned to it.

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a green grocer had 623 oranges. He packed them in cartons, which could only take 11 oranges or 12 oranges respectively, and no o

Luba_88 [7]

Answer:51 crates could have 12 oranges and one crate could hold 11 oranges.

Step-by-step explanation: 623 / 12 is 51.9... 51 x 12 is 612. 612 + 11 is 623 math checks out.

8 0

1 year ago

Find the absolute maximum and minimum values of f(x,y)=xy−4x in the region bounded by the x-axis and the parabola y=16−x2.

skad [1K]

Answer:

The absolute maximum and minimum is $20\; \text{and} -20.$

Step-by-step explanation:

We first check the critical points on the interior of the domain using the

first derivative test.

$f_x=y-4=0$

$f_y=x=0$

The only solution to this system of equations is the point (0, 4), which lies in the domain.

$f_{xx}=0, \;f_{yy}=0\; \text{and}\; f_{xy}=-1$

$\Rightarrow f_{xx}f_{yy}-f_{xy}=o-1=-1$

$\therefore (0,4)$ is a saddle point.

Boundary points - $(4,0), (-4,0), (0,16)$

Along boundary $y=16-x^2$

$f=x(16-x^2)-4x$

$=16x-x^3-4x$

$\Rightarrow f^'=16-3x^2-4=0$

$\Rightarrow 3x^2=12$

$\Rightarrow x=\pm2,\;\;y=14$

Values of f(x) at these points.

$\begin{array}{}(4,0)=-16\\(-4,0)=16\\(0,16)=0\\(2,14)=20\\(-2,14)=-20\end{array}$

Therefore, the absolute maximum and minimum is $20\; \text{and} -20.$

6 0

3 years ago

Solve the problem below:<br><br>9+10=

Elan Coil [88]

Answer:

19

Step-by-step explanation:

qwertyuiop[sdfghjkl;zxcvbnm,.

4 0

2 years ago

Solve the following system of equations by substitution. Show all steps.

Alinara [238K]

Answer:

Given system of equations:

$\begin{cases}f(x)=-x^2+2x+3\\g(x)=-2x+3\end{cases}$

To solve by substitution, equate the equations and solve for x:

$\begin{aligned}f(x) & = g(x)\\\implies -x^2+2x+3 & = -2x+3\\-x^2+4x & = 0\\x^2-4x & = 0\\x(x-4) & = 0\\\implies x & = 0\\\implies x-4 & = 0 \implies x=4\end{aligned}$

Therefore, the x-values of the solution are $x = 0$ and $x = 4$ .

To find the y-values of the solution, substitute the found values of x into the functions:

$f(0)=-(0)^2+2(0)+3=3$

$g(0)=-2(0)+3=3$

$f(4)=-(4)^2+2(4)+3=-5$

$g(4)=-2(4)+3=-5$

Therefore, the solutions to the given system of equations are:

$(0, 3)$ and $(4, -5)$

4 0

2 years ago

Jeremy will roll a number cube, numbered 1−6

Marina CMI [18]

Answer:

Step-by-step explanation:

p(even) = 3/6

p number 3 = 1/6

p (even then number 3) = 3/6 * 1/6 = 3/36

7 0

2 years ago