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Rasek [7]
3 years ago
5

-3(p-7) > 21 solve for p​

Mathematics
1 answer:
Goryan [66]3 years ago
5 0

Answer:

p < 0

Step-by-step explanation:

Given

- 3(p - 7) > 21

Divide both sides by - 3, reversing the symbol as a result of dividing by a negative quantity.

p - 7 < - 7 ( add 7 to both sides )

p < 0

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Nicole has 27 cars available to rent.
Schach [20]

Answer

27 - R = C

if she rented 16 of them then

27 - 16 = C   And C = 11

3 0
3 years ago
Can someone help me with my math problem pls my teacher is on my back about this
Karo-lina-s [1.5K]

Answer:

A: 8

B: 96

I'm not sure on C, sorry.

5 0
3 years ago
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Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, on
insens350 [35]
1) We have that there are in total 6 outcomes If we name the chips by 1a, 1b, 3 ,5 the combinations are: 1a,3 \ 1b, 3 \1a, 5\ 1b, 5\ 3,5\1a,1b. Of those outcomes, only one give Miguel a profit, 1-1. THen he gets 2 dollars and in the other cases he lose 1 dollar. Thus, there is a 1/6 probability that he gets 2$ and a 5/6 probability that he loses 1$.
2) We can calculate the expected value of the game with the following: E=\frac{1}{6}*2- \frac{5}{6} *1. In general, the formula is E= \sum{p*V} where E is the expected value, p the probability of each event and V the value of each event. This gives a result of E=2/6-5/6=3/6=0.5$ Hence, Miguel loses half a dollar ever y time he plays.
3) We can adjust the value v of the winning event and since we want to have a fair game, the expecation at the end must be 0 (he must neither win or lose on average). Thus, we need to solve the equation for v:
0=\frac{1}{6}v -\frac{5}{6} =0. Multiplying by 6 both parts, we get v-5=0 or that v=5$. Hence, we must give 5$ if 1-1 happens, not 2.
4) So, we have that the probability that you get a red or purple or yellow sector is 2/7. We have that the probability for the blue sector is only 1/7 since there are 7 vectors and only one is blue. Similarly, the 2nd row of the table needs to be filled with the product of probability and expectations. Hence, for the red sector we have 2/7*(-1)=-2/7, for the yellow sector we have 2/7*1=2/7, for the purple sector it is 2/7*0=0, for the blue sector 1/7*3=3/7. The average payoff is given by adding all these, hence it is 3/7.
5) We can approach the problem just like above and set up an equation the value of one sector as an unknown. But here, we can be smarter and notice that the average outcome is equal to the average outcome of the blue sector.  Hence, we can get a fair game if we make the value of the blue sector 0. If this is the case, the sum of the other sectors is 0 too (-2/7+0+2/7) and the expected value is also zero.
6) We want to maximize the points that he is getting. If he shoots three points, he will get 3 points with a probability of 0.30. Hence the average payoff is 0.30*3=0.90. If he passes to his teammate, he will shoot for 2 points, with a success rate of 0.48. Hence, the average payoff is 0.48*2=0.96. We see that he should pass to his player since 0.06 more points are scored on average.
7) Let us use the expections formula we mentioned in 1. Substituting the possibilities and the values for all 4 events (each event is the different profit of the business at the end of the year).
E=0.2*(-10000)+0.4*0+0.3*5000+0.1*8000=-2000+0+1500+800=300$
This is the average payoff of the firm per year.
8) The firm goes even when the total profits equal the investment. Suppose we have that the firm has x years in business. Then x*300=1200 must be satisfied, since the investment is 1200$ and the payoff per year is 300$. We get that x=4. Hence, Claire will get her investment back in 4 years.
8 0
3 years ago
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four families go to the cinema. the reid family take 2 adults and 2 children for £18 ; the mghee family take 1 senior, 2 adults
RoseWind [281]

Answer:

\pounds 26.50

Step-by-step explanation:

Let

x = cost for one adult

y = cost for one child

z = cost for one senior.

<u>The Reid family:</u>

take 2 adults and 2 children and paid 2x+2y that is \pounds 18, so

2x+2y=18

<u>The Mghee family:</u>

take 1 senior, 2 adults and 1 child and paid x+2x+y that is \pounds 18.50, so

x+2x+y=18.50

<u>The Griffiths family:</u>

take 1 senior and 3 adults and paid z+3x that is \pounds 19.50, so

z+3x=19.50

You get the system of three equations:

\left\{\begin{array}{l}2x+2y=18\\ \\z+2x+y=18.50\\ \\z+3x=19.50\end{array}\right.

From the first equation:

2y=18-2x\\ \\y=9-x

From the third equation:

z=19.50-3x

Substitute them into the second equation:

19.50-3x+2x+9-x=18.50\\ \\-3x+2x-x=18.50-19.50-9\\ \\-2x=-10\\ \\2x=10\\ \\x=5

Then

y=9-5=4\\ \\z=19.50-3\cdot 5=19.50-15=4.50

Hence,

the cost for one adult is \pounds 5

the cost for one child is \pounds 4

the cost for one senior is \pounds 4.50

<u>The Linton family</u> takes 1 senior, 2 adults and 3 children and paid

\pounds 4.50+2\cdot \pounds 5+3\cdot \pounds 4=\pounds 26.50

3 0
3 years ago
What is 0.375 expressed as a fraction
Leno4ka [110]
0.735 expressed as a fraction is 3/8
7 0
2 years ago
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