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julia-pushkina [17]
3 years ago
13

The picture show the models that four students each constructed out of marshmallows and gumdrop candies to illustrate the differ

ence between atoms and molecules.
Which model is the most effective?
A
Model 1 is the most effective because it shows that elements are always organized in orderly arrays.

B
Model 2 is the most effective because it shows that atoms are bound to each other and molecules are made of a single element.

C
Model 3 is the most effective because it shows that molecules can be made out of more than one type of atom.

D
Model 4 is the most effective because it shows that both atoms and molecules can be composed of different elements.

Chemistry
1 answer:
Oduvanchick [21]3 years ago
8 0

Model 3 is the most effective because it shows that molecules can be made out of more than one type of atom

Explanation:

The most effective model is the first model which shows that molecules can be made out of more than one type of atom

  • An element is a distinct substance that cannot be split up into simpler substances.
  • When elements combine together they either form compounds or molecules.
  • Molecules are usually atoms that are covalently bonded together. They have very fascinating and unique properties.
  • The third model perfect shows how molecules can be made up of the same atom and also different atoms.
  • Atoms in molecules share their valence electrons.

Learn more:

covalent bonds brainly.com/question/11730855

#learnwithBrainly

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Answer:

P_H =2.86

c=1.4\times 10^{-4}

Explanation:

first write the equilibrium equaion ,

C_3H_6O_3  ⇄ C_3H_5O_3^{-}  +H^{+}

assuming degree of dissociation \alpha =1/10;

and initial concentraion of C_3H_6O_3 =c;

At equlibrium ;

concentration of C_3H_6O_3 = c-c\alpha

[C_3H_5O_3^{-}  ]= c\alpha

[H^{+}] = c\alpha

K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}

\alpha is very small so 1-\alpha can be neglected

and equation is;

K_a = {c\alpha \times \alpha}

[H^{+}] = c\alpha = \frac{K_a}{\alpha}

P_H =- log[H^{+} ]

P_H =-logK_a + log\alpha

K_a =1.38\times10^{-4}

\alpha = \frac{1}{10}

P_H= 3.86-1

P_H =2.86

composiion ;

c=\frac{1}{\alpha} \times [H^{+}]

[H^{+}] =antilog(-P_H)

[H^{+} ] =0.0014

c=0.0014\times \frac{1}{10}

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Answer:

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Explanation:

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Answer:

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Explanation:

We can solve this problem using the relation:

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<em>∴ The freezing point of the solution is - 4.39 °C.</em>

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