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Yuliya22 [10]
3 years ago
13

Hey I'm a newbie any help please with this

Chemistry
1 answer:
solniwko [45]3 years ago
4 0
6 A
7 A
8 B
9 B
10 A
11 C
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How many Liters of H2O are in 1.50 g H2O?
zlopas [31]

Answer:18.02 grams

The average mass of one mole of H2O is 18.02 grams.

Explanation: we need to find the moles of water in 1 L of water or 1000mL of water. Taking the density of water to be 1g/mL, 1000mL of water= 1000g water.

Therefore, number of moles= given mass of water(1000)/molecular mass of water(18)

Moles =1000/18= 55.55

So total molecules in 55.55 moles= 55.55* 6.022*10^23 = 334.52*10^23 molecules

=3.34*10^25 molecules of water.

:)

6 0
3 years ago
Read 2 more answers
What volume of 0.100 m sodium chloride must be added to 75.0 ml of 0.200 m lead(ii) nitrate to precipitate all of the lead ions?
Svetradugi [14.3K]
Reaction for precipitation is
Pb(NO3)2(aq) + 2Nacl(aq)→PbCL2(s)+2NaNO3(aq)
The given reaction is 
The mol of Nacl required is =2×mol of Pb(NO3)2 which is present.
∴M(Nacl)×V(Nacl) =2×M(Pb(NO3)2 ×V(Pb(NO3)2
o.100M×V(Nacl)=2×0.200 MX75.0ML
V(Nacl = 300mL.
5 0
3 years ago
What type of chemical reaction is given by the following balanced equation:<br> Al₂O3 → AL+ O₂
rjkz [21]

Answer:

Decomposition

Explanation:

3 0
3 years ago
6. What is the wavelength (in meters) of the electromagnetic carrier wave transmitted by The Sports
Vsevolod [243]

Answer:

wavelength = 2.81 m

Explanation:

Given that,

The frequency of the Sports  Fan radio station, f = 106.4 MHz

We need to find the wavelength (in meters) of the electromagnetic carrier wave. The relation between frequency and wavelength is given by :

c=f\lambda

Where,

\lambda is wavelength

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{106.4\times 10^6}\\\\\lambda=2.81\ m

So, the wavelength of the electromagnetic carrier wave is 2.81 m.

8 0
3 years ago
Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.30 MJ o
Sunny_sXe [5.5K]

Answer:

97 000 g Na

Explanation:

The absortion (or liberation) of energy in form of heat is expressed by:

q=m*Cp*ΔT

The information we have:

q=1.30MJ= 1.30*10^6 J

ΔT = 10.0°C = 10.0 K (ΔT is the same in °C than in K)

Cp=30.8 J/(K mol Na)

If you notice, the Cp in the question is in relation with mol of Na. Before using the q equation, we can find the Cp in relation to the grams of Na.

To do so, we use the molar mass of Na= 22.99g/mol

Cp= \frac{30.8J}{K*mol Na}*\frac{1 mol Na}{22.99 g Na}=1.34\frac{J}{K*g Na}

Now, we are able to solve for m:

m=\frac{1.30*10^6 J}{1.34\frac{J}{K*g Na} *10.0K}=\frac{1.30*10^6J}{13.4\frac{J}{g Na} }  = 9.70*10^4 g Na=97 Kg Na=97 000 g Na

7 0
3 years ago
Read 2 more answers
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