Answer:18.02 grams
The average mass of one mole of H2O is 18.02 grams.
Explanation: we need to find the moles of water in 1 L of water or 1000mL of water. Taking the density of water to be 1g/mL, 1000mL of water= 1000g water.
Therefore, number of moles= given mass of water(1000)/molecular mass of water(18)
Moles =1000/18= 55.55
So total molecules in 55.55 moles= 55.55* 6.022*10^23 = 334.52*10^23 molecules
=3.34*10^25 molecules of water.
:)
Reaction for precipitation is
Pb(NO3)2(aq) + 2Nacl(aq)→PbCL2(s)+2NaNO3(aq)
The given reaction is
The mol of Nacl required is =2×mol of Pb(NO3)2 which is present.
∴M(Nacl)×V(Nacl) =2×M(Pb(NO3)2 ×V(Pb(NO3)2
o.100M×V(Nacl)=2×0.200 MX75.0ML
V(Nacl = 300mL.
Answer:
wavelength = 2.81 m
Explanation:
Given that,
The frequency of the Sports Fan radio station, f = 106.4 MHz
We need to find the wavelength (in meters) of the electromagnetic carrier wave. The relation between frequency and wavelength is given by :

Where,
is wavelength

So, the wavelength of the electromagnetic carrier wave is 2.81 m.
Answer:
97 000 g Na
Explanation:
The absortion (or liberation) of energy in form of heat is expressed by:
q=m*Cp*ΔT
The information we have:
q=1.30MJ= 1.30*10^6 J
ΔT = 10.0°C = 10.0 K (ΔT is the same in °C than in K)
Cp=30.8 J/(K mol Na)
If you notice, the Cp in the question is in relation with mol of Na. Before using the q equation, we can find the Cp in relation to the grams of Na.
To do so, we use the molar mass of Na= 22.99g/mol

Now, we are able to solve for m:
=97 000 g Na