For this case we must solve each of the functions.
We have then:
f (x) = x2 - 9, and g (x) = x - 3
h (x) = (x2 - 9) / (x - 3)
h (x) = ((x-3) (x + 3)) / (x - 3)
h (x) = x + 3
f (x) = x2 - 4x + 3, and g (x) = x - 3
h (x) = (x2 - 4x + 3) / (x - 3)
h (x) = ((x-3) (x-1)) / (x - 3)
h (x) = x-1
f (x) = x2 + 4x - 5, and g (x) = x - 1
h (x) = (x2 + 4x - 5) / (x - 1)
h (x) = ((x + 5) (x-1)) / (x - 1)
h (x) = x + 5
f (x) = x2 - 16, and g (x) = x - 4
h (x) = (x2 - 16) / (x - 4)
h (x) = ((x-4) (x + 4)) / (x - 4)
h (x) = x + 4
Assuming that is a 24 the answer would be 24[10] = 240 but if that is the question 2 and the number is just 4 the answer is just 40
Answer:
A. a quadratic function can only have one y-intercep
Where's the net. We need the net to answer the question
Answer:
$440
Step-by-step explanation:
notes $2 - n
notes $10 - m
n + m = 80 ----------> m = 80 - n
1 - 2/5 = 3/5
45 * $2 + 35 * $10 = 90 + 350 = $440
