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2 years ago

If you vertically compress the absolute value parent function, f(x) = |x|, by a factor of 3, what is the equation of the new fun

ction?

Mathematics

1 answer:

sveticcg [70]2 years ago

6 0

$f(x) = \frac{1}{3} |x|$

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bill and sam have a coupon for a pizza with 1 topping. The choices of toppings are: pepperoni, sausage, mushrooms, green peppers

cricket20 [7]

Well there are 6 toppings. For one person to select sausage, it is $\frac{1}{6}$ . For two people, multiply them together and the probability is $\frac{1}{36}$

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2 years ago

Assume that a procedure yields a binomial distribution with n=3 trials and a probability of success of p=0.300. use a binomial p

NNADVOKAT [17]

$\mathbb P(X=x)=\begin{cases}\dbinom3xp^x(1-p)^{3-x}&\text{for }0\le x\le3\\\\0&\text{otherwise}\end{cases}$

$\implies\mathbb P(X=2)=\dbinom32(0.3)^2(0.7)^1=0.189=18.9\%$

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3 years ago

What does the series represent to the bike owner answer all plz :)

zlopas [31]

Answer:

lol or i could just answer it on here

Step-by-step explanation:

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2 years ago

The intensity of a sound varies inversely where of its distance from the source at a distance of 1 meter the intensity of a jet

xz_007 [3.2K]

Answer:

1/250 W/m² or 0.004 W/m² or 4 mW/m²

Step-by-step explanation:

The cargo worker is (50 m)/(1 m) = 50 times the reference distance. The intensity varies as the inverse of the square of the distance, so will be ...

(1/50)²×(10 W/m²) = 10/2500 W/m² = 1/250 W/m²

This might be more conveniently written as 4 mW/m².

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2 years ago

The wildlife department has been feeding a special food to rainbow trout fingerlings in a pond. based on a large number of obser

Liono4ka [1.6K]

The normal distribution curve for the problem is shown below

We need to standardise the value X=405.5 by using the formula

$z-score= \frac{X-Mean}{Standard Deviation}$
$z-score= \frac{405.5-402.7}{8.8} =0.32$

We now need to find the probability of z=0.32 by reading the z-table

Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

$P(Z\ \textgreater \ z)=1 - P(Z\ \textless \ z)$

from the z-table, the reading $P(Z\ \textless \ 0.32)$ gives 0.6255

hence,
$P(Z\ \textgreater \ 0.32)=1-0.6255=0.3475$

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%

7 0

2 years ago