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3 years ago

14

he quadrilateral PQRS in the diagram is a parallelogram. Let P'Q'R'S' be the image of PQRS after applying a dilation centered at

a point O (not shown) with scale factor 3.

1 answer:

yKpoI14uk [10]3 years ago

6 0

Answer:

P”Q=3PQ

Step-by-step explanation:

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Help due today find the slope

Y_Kistochka [10]

Answer:

27.) -4

28.) 3

29.) -2

30.) -3

Step-by-step explanation:

Hope this helped!

3 0

3 years ago

Based on the given angle measures, which triangle has side length measures that could be correct?

Likurg_2 [28]

Answer

The triangle in the figure 4 is correct .

Reason

by using the trignometric identity

$tan\theta = \frac{Perpendicular}{Base}$

Thus

$tan 30^{\circ} = \frac{Perpendicular}{Base}$

$tan 30 ^{\circ} =\frac{1}{\sqrt{3}}$

Now in the figure (1)

$tan 30^{\circ} = \frac{13.9}{8}$

$\frac{1}{\sqrt{3}} = \frac{13.9}{8}$

on simplify

$0.5774 \neq 1.7375$

thus side length measures in the figure (1) is not correct .

Now in the figure (2)

$tan30^{\circ} =\frac{16}{8} \\ \frac{1}{\sqrt{3}} =\frac{16}{8} \\ 0.577 \neq 2$

thus side length measures in the figure (2) is not correct .

Now in the figure (3)

$tan 30 ^{\circ} = \frac{8}{16} \\ \frac{1}{\sqrt{3}} =\frac{8}{16} \\ 0.577\neq0.5$

thus side length measures in the figure (3) is not correct .

Now in the figure (4)

$tan30^{\circ} = \frac{8}{13.9} \\ \frac{1}{\sqrt{3}} =\frac{8}{13.9}\\ 0.577 = 0.576(approx)$

Therefore the figure (4) is correct triangle has side length measures that could be correct

Hence proved

8 0

2 years ago

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An equation is shown below:

zloy xaker [14]

I believe that the answer is x=2.

7 0

3 years ago

Please help!!!!!!!!!!

Delvig [45]

Answer:

im pretty sure that the answer is D i know for a fact that it is D

3 0

2 years ago

(-8) X 2/3 i NEED the answer help me

Vlada [557]

Answer:

-5.33333333 or -5.3

Step-by-step explanation:

-8 * 2/3 =

-5.33333

5 0

3 years ago

Read 2 more answers