1. Open the compass to a little more than halfway across the line segment XY. Draw an arc centered at the first endpoint X across the line segment XY. Without changing the width of the compass, place the compass tip on the
second endpoint Y. Draw a second arc across the line segment XY.
2. Line up a straightedge with the intersection of the arcs above the line XY,
and the intersection of the arcs below the line. Draw a line connecting
these two points. The line you draw is a perpendicular bisector. It
bisects the line XY at a right angle.
3. Use a compass and straightedge to construct the bisectors of the line YZ as you did with the first line segment. Extend the bisectors long enough that they intersect. The point of their intersection is the center of the circle.
4. The radius of a circle is the distance from the center to any point on the circle’s edge.
To set the width, place the tip of the compass on the center of the
circle, and open the compass to any one of your original points.Swing the compass around 360 degrees so that it draws a complete circle. The circle should pass through all three points.
Answer:
√50
Step-by-step explanation:
Use Pythagorean Theorem: a^2+b^2=c^2
5^2+5^2=c^2
25+25=c^2
50=c^2
c=√50
Answer:
<u>The equations for each function:</u>
- A(t) = 60 - 6t
- B(t) = 42 - 3t
<em>The lines plotted, see attached</em>
<u>The point at which both the snowmen have same height:</u>
- 60 - 6t = 42 - 3t
- 6t - 3t = 60 - 42
- 3t = 18
- t = 6
<u>The required interval is </u>
Use the formula SA=a+1/2ps
a=area of the base
p= perimeter of the base
s= slant height
<h3>☂︎ Answer :- </h3>
<h3>☂︎ Solution :- </h3>
- LCM of 5 , 18 , 25 and 27 = 2 × 3³ × 5²
- 2 and 3 have odd powers . To get a perfect square, we need to make the powers of 2 and 3 even . The powers of 5 is already even .
In other words , the LCM of 5 , 18 , 25 and 27 can be made a perfect square if it is multiplied by 2 × 3 .
The least perfect square greater that the LCM ,
☞︎︎︎ 2 × 3³ × 5² × 2 × 3
☞︎︎︎ 2² × 3⁴ × 5²
☞︎︎︎ 4 × 81 × 85
☞︎︎︎ 100 × 81
☞︎︎︎ 8100
8100 is the least perfect square which is exactly divisible by each of the numbers 5 , 18 , 25 , 27 .
