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Juliette [100K]
3 years ago
7

HELP ME ON GEOMETRY!!​

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

12 units²

Step-by-step explanation:

The two are congruent, so C'D' is still 6units long. L*W = 6 * 2 = 12 units^2

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Question 25 of 25
frez [133]

Answer:

It is actually 2 and -6.

Step-by-step explanation:

i hope i helped <33

6 0
3 years ago
Amelia spent an hour an a half on a drawing .At the end she said that it was 75% done.How much time do she needs and how much ti
noname [10]
You can think of an hour and a half as 75% itself already because you have 3/4 or three thirty minute periods. So every 1/4 is a 30 minute period, and if you multiply 1/4 by 4 you get 4/4 which you ten can convert to 2 hours or 4, 30 minute time periods. (I’m sorry if I explained this in a very confusing manner). It will take Amelia 2 hours in total to finish her drawing.
7 0
3 years ago
What is the perimeter of the figure to the nearest tenth of a millimeter
torisob [31]
The answer would be 18mm because 6+6+3+3 considering that there are 4 sides.
6 0
4 years ago
Read 2 more answers
Real World Scenario:
iragen [17]

The distance of a train from the city depends on the speed, the time of

travel, and direction of motion of the train.

Correct responses:

  • Distance Train A is from the city: <u>750 - 75·t</u>
  • Distance Train B is from the city: 50·t
  • After <u>six</u> hours, the two trains are the same distance from the city
  • At that time both trains will be <u>300</u> miles away

1) From the time of departure of Train B to just before 6 hours after Train B's departure; 0 ≤ t < 6 hours

2) At time period, t > 6 hours

3) 250 miles

<h3>Method used to find the above response</h3>

Given:

The distance of train A from the city = 750 miles

Speed of train A = 75 mph

Time at which Train B leaves the city = When Train A is 750 miles from the city

Speed of Train B = 50 mph

Solution:

The equations are;

  • Distance of Train A from the city is; <u>x₁ = 750 - 75·t</u>
  • Distance of Train B from the city is <u>x₂ = 50·t</u>

When the train are the same distance from the city, we have;

750 - 75·t = 50·t

750 = 50·t + 75·t = 125·t

Therefore;

  • t = \mathbf{\dfrac{750}{125}} = 6

The time it takes the two trains to be the same distance from the city is 6 hours.

Which gives;

  • After <u>6</u> hours, the two trains are the same distance from the city.

The distance the trains will be after 6 hours is therefore;

750 - 75 × 6 = 300

The distance of the trains from the city after 6 hours = 300 miles

Therefore, we have;

  • At that time both trains will be <u>300</u> miles away

1) The time period Train A is further from the city is before the first 6 hours elapse; <u>0 hours ≤ t < 6 hours</u>

2) The Train B is further from the city after 6 hours of its departure from the city; <u>t > 6 hours</u>

3) The distance of Train A from the city after 4 hours is given as follows;

x₁ = 750 - 75 × 4 = 450

x₁ = 450 miles

The distance of Train B from the city after 4 hours is; x₂ = 50 × 4 = 200

x₂ = 200 miles

Therefore;

  • The distance between the trains after 4 hours = 450 miles - 200 miles = <u>250 miles</u>

Learn more about distance and time relationship equation here:

brainly.com/question/10804931

3 0
2 years ago
tom paid $16 for 6 audio cassettes. Which proportion can be used to find the amount of money (m) he would pay for 9 audio casset
tigry1 [53]

Answer:

Step-by-step explanation:

From the question, Tom paid $16 for 6 audio cassettes and we are told to find the proportion to get the amount of money (m) he would pay for 9 audio cassettes. To get this, we have to know the amount of the cost of 1 audio cassette. Since Tom paid $16 for 6 audio cassettes, 1 audio cassette will cost:

= $16/6

= $2.67

1 audio cassette will cost $2.67

The amount of money spent will depend on the number of audio cassettes. Therefore,

m = $2.67 × n

m = $2.67n

where n = number of audio cassette

The amount of money he'll pay for 9 cassette will be:

m = $2.67n

m = $2.67 × 9

m = $24.03

7 0
3 years ago
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