Answer:
1. X-intercept is 5 Y-intercept is 4 (Red Line)
2. X-intercept is 1 Y-intercept is 2 (Blue Line)
3. X-intercept is -2 Y-intercept is 4 (Green Line)
Step-by-step explanation:
DESMOS graphing calculator. Here is the graph showing my work:
First you have to know BODMAS/BIDMAS (idk if all schools teach it like this) but this is the order in which you complete questions so it’s Brackets, Indices, Division/Multiplication, Addition/Subtraction
a) 5^2 is 5x5 which equals 25 1 to the power of anything is always 1 and 2^4 is 2x2x2x2 which is 16
So 5^2-1^5x2^4 = 25-1x16 which is then 25-16 = 9
b) 7^2+4^3 divided by 2^5 so 7^2 is 7x7 which = 49 then 4^3 means 4x4x4 = 64 and 2^5 is 2x2x2x2x2 which equals 32 so
7^2+4^3 divides by 2^5 is 49+64/32 = 49+2 which is 51
Answer:
A
Step-by-step explanation:
x² - 4x - 5 = 0
x² - 5x + x - 5 = 0
x(x - 5) + (x -5) = 0
(x - 5)(x + 1) = 0
x - 5 = 0 ; x + 1 = 0
x = 5 ; x = -1
Z4+x33[23+32)
JanalN
Uhajaia
Jain
The actual width of the room is 20 ft and the actual length of the room is 15 ft
Since on the scale, 2 in : 5 ft and the width of the room on the drawing is 8 in.
Let the actual width of the room is w.
The ratio of the drawing to actual width is 8 in : w
So, 2 in : 5 ft = 8 in : w
2 in/5 ft = 8 in/w
So, w = 8 in × 5 ft/2 in
w = 4 × 5 ft
w = 20 ft
Also, the length of the room on the drawing on the drawing is 6 in.
Let the actual length of the room is L.
The ratio of the drawing to actual length is 6 in : L
So, 2 in : 5 ft = 6 in : L
2 in/5 ft = 6 in/L
So, L = 6 in × 5 ft/2 in
L = 3 × 5 ft
L = 15 ft
So, the actual width of the room is 20 ft and the actual length of the room is 15 ft.
Learn more about scale drawing here:
brainly.com/question/25324744