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kirill115 [55]
3 years ago
12

Which factors are the most important in choosing which house to buy?

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
8 0
The answer would be the answer b
Bogdan [553]3 years ago
3 0
I would say B in all honesty. Others probably would want A
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Help me pleaseeeeeeeee
Hitman42 [59]

Answer:

Subtract 5 from each side

Step-by-step explanation:

This would put all coefficients on one side.

7 0
2 years ago
Which number is 2,678 less than 10,000
lesantik [10]
Less than means to subtract so 2678 less than 10000 will be
=10000-2678
=7322
3 0
3 years ago
Read 2 more answers
A sequence is defined recursively using the formula f(n + 1) = -0.5f(n). If the first term of the sequence is 120, what is f(5)?
PolarNik [594]

Answer: 7.5

Step-by-step explanation:

The given formula tells us that the next term f(n+1) of the sequence is -0.5 times the previous term f(n)

First term of the sequence is f(1) = 120

Second term of the sequence is f(2) = f(1+1) = -0.5 f(1) = -0.5 (120) = -60

Third term of the sequence is f(3) = f(2+1) = -0.5 f(2) = -0.5 (-60) = 30

Fourth term of the sequence is f(4) = f(3+1) = -0.5 f(3) = -0.5 (30) = -15

Fifth term of the sequence is f(5) = f(4+1) = -0.5 f(4) = -0.5 (-15) = <em>7.5</em>

3 0
3 years ago
Read 2 more answers
What is 8/16 I will give brainlyist
zepelin [54]

Answer:one half

Step-by-step explanation:

3 0
3 years ago
Can you see an easy way to work out the value of <img src="https://tex.z-dn.net/?f=%5Csqrt%7B%201%5E3%20%2B%202%5E3%20%2B%203%5E
Lina20 [59]

We have the sum of cubes identity

a^3 + b^3 = (a + b) (a^2 - ab + b^2)

and observing that 1 + 4 = 2 + 3, we have

1^3 + 4^3 = (1 + 4) (1^2 - 4 + 4^2) = 5 \times 13

and

2^3 + 3^3 = (2 + 3) (2^2 - 6 + 3^2) = 5 \times 7

Then

\sqrt{1^3+2^3+3^3+4^3+5^3} = \sqrt{5\times13 + 5\times7 + 5\times5^2} = \sqrt{5 \times (20 + 25)} \\\\ ~~~~~~~~ = \sqrt{5^2 \times (4 + 5)} = \sqrt{5^2\times9} = \sqrt{5^2\times3^2} = 5\times3 = \boxed{15}

Alternatively, we have the well-known sum of cubes formula

\displaystyle \sum_{i=1}^n i^3 = \frac{n^2(n+1)^2}4

The sum under the square root is this sum with n=5. Then

1^3+2^3+3^3+4^3+5^3 = \dfrac{5^2\times6^2}4 = 225 = 15^2

and so the square root again reduces to 15.

5 0
1 year ago
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