Answer:
By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single
Step-by-step explanation:
let p1 be the proportion of elementary teachers who were single
let p2 be the proportion of high school teachers who were single
Then, the null and alternative hypotheses are:
: p2=p1
: p2>p1
We need to calculate the test statistic of the sample proportion for elementary teachers who were single.
It can be calculated as follows:
where
- p(s) is the sample proportion of high school teachers who were single (
) - p is the proportion of elementary teachers who were single (
)
- N is the sample size (180)
Using the numbers, we get
≈ 1.88
Using z-table, corresponding P-Value is ≈0.03
Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)
-2m - 5m - 8 = 3 + (-7) + m
-7m - 8 = 3 - 7 + m
-7m - 8 = m - 4 <=== here is one
m - 4 = -7m - 8 <=== another one
-8 - 7m = -4 + m <== and another one
X=$30
y=$60
1 hour job- 60x1=60+30=90
3 hour job-60x3=180+30=210
73/4 is the answer to your question sir your welcome
V=πr2h
v=π(5)^2(10)
v=250π
v=785 inches cubed