I’m just trying so much better to talk now but it’s just a good 256
Answer:
4x-3y+12=0 is required eqn
Step-by-step explanation:
Let, 3,8 be x1,y1
9,16 be x2,y2
Now,
Eqn of st.line is y-y1 = y2-y2/x2-x1 * (x-x1)
y-8 = 16-8/9-3 * (x-3)
y-8 = 4/3*(x-3)
3y-24 = 4x-12
4x-3y+12=0 is required eqn
Answer:
5r-2
Step-by-step explanation:
Answer:
x=
−3
4
y+
−19
4
Step-by-step explanation:
