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iren2701 [21]
3 years ago
8

How do you solve this and what is the answer

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
6 0

Answer:

x = 38°

Step-by-step explanation:

An external angle is equal to the sum of the opposite internal angles of a triangle. Either of the internal angles at the base can be found as the supllement of its external angle.

∠OLM = 180° -134° = 46°

Then

... x +46° = 84°

... x = 38° . . . . . subtract 46°

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How to find the length of the hypotenuse correct to one decimal place<br>​
hichkok12 [17]

Answer:

If you are provided with the lengths of two sides a triangle, you can find the third side using the Pythagorean Theorem: a^2+b^2=c^2.

Variable c represents the length of the hypotenuse, and variables a and b represent the lengths of the other two sides.

Please mark as Brainliest! :)

5 0
2 years ago
If the angles are represented in degrees, find both angles: sin(x+7)=cos(4x+8)
garri49 [273]

Answer:

m\angle 1 = 22\degree

m\angle 2 = 68\degree

Step-by-step explanation:

\sin(x + 7) =  \cos(4x + 8) \\  \sin(x + 7) =  \sin \{90  - (4x + 8) \} \\  \{ \because \cos \theta =  \sin(90 \degree -  \theta)  \}\\  \therefore \: (x + 7) = 90 - (4x + 8) \\ x + 7 + 4x + 8 = 90 \\ 5x = 90 - 15 \\ 5x = 75 \\ x =  \frac{75}{5}  \\ x = 15

(x + 7)° = (15 + 7)° = 22°

(4x + 8)° = (4*15 + 8)° = (60 + 8)° = 68°

m\angle 1 = 22\degree

m\angle 2 = 68\degree

7 0
2 years ago
Need help with this one will mark brainliest
const2013 [10]
1,-7 would be the answer I believe
7 0
3 years ago
Read 2 more answers
Find all the zeroes of the equation(with simple steps).
uysha [10]

<u>Answer-</u>

<em>The zeros are, 5,\ -5,\ 4i,\ -4i</em>

<u>Solution-</u>

\Rightarrow -3x^4+27x^2+1200=0

\Rightarrow -3(x^2)^2+27(x^2)+1200=0

Here,

a = -3, b = 27, c = 1200

So,

x^2=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

=\dfrac{-27\pm \sqrt{-27^2-4\cdot (-3)\cdot 1200}}{2\cdot (-3)}

=\dfrac{-27\pm \sqrt{729+14400}}{-6}

=\dfrac{-27\pm 123}{-6}

=\dfrac{-27+123}{-6},\ \dfrac{-27- 123}{-6}

=\dfrac{96}{-6},\ \dfrac{-150}{-6}

=-16,\ 25

So,

\Rightarrow x^2=25,\ -16

\Rightarrow x=\sqrt{25},\ \sqrt{-16}

\Rightarrow x=5,\ -5,\ 4i,\ -4i

8 0
3 years ago
Determine whether the graph is a function
S_A_V [24]
Do the vertical line test
16. Function
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