I'm going to rewrite f(x) and g(x) so that I don't get confused.
Based on your description:
f(x) = (2x) + x - 1 simplified to 4x + x - 1
g(x) = x + 3x - 3
Now we handle parts A-D.
A. f(x) + g(x)
We combine like terms. 4x + 5x + x + 3x - 1 - 3 = 5x + 4x - 4 B. f(x) - g(x)
Again combine like terms like normal except this time subtracting. 4x - x + x - 3x - 1 - (- 3) = 3x - 2x + 2 C. 2f(x) + 2g(x) Multiply, then again CLT 2f(x) = 8x + 2x - 2 2g(x) = 2x + 6x - 6 Combine like terms to get 10x + 8x - 8 D. 2f(x) - 2g(x) Use the same 2f(x) and 2g(x) terms and this time just subtract. You get 6x - 4x + 4
Add 9 to both sides to get 3 |y-5| = 9. Divide both sides by 3 to get |y-5| = 3. Now get both positive and negatives of the absolute. y-5 = -3. Add 5 to both sides to get y = 2. Now do the original equation. Add 5 to 3 to get 8. Y = 2 or 8.