Given the functions f(x) = left parenthesis 2 x right parenthesis squared plus x minus 1

1 answer:

6 0

I'm going to rewrite f(x) and g(x) so that I don't get confused.

Based on your description:

f(x) = (2x) $^{2}$ + x - 1 simplified to 4x $^{2}$ + x - 1

g(x) = x $^{2}$ + 3x - 3

Now we handle parts A-D.

A. f(x) + g(x)

We combine like terms.

4x $^{2}$ + 5x $^{2}$ + x + 3x - 1 - 3 = 5x $^{2}$ + 4x - 4

B. f(x) - g(x)

Again combine like terms like normal except this time subtracting.

4x $^{2}$ - x $^{2}$ + x - 3x - 1 - (- 3) = 3x $^{2}$ - 2x + 2

C. 2f(x) + 2g(x)

Multiply, then again CLT

2f(x) = 8x $^{2}$ + 2x - 2
2g(x) = 2x $^{2}$ + 6x - 6

Combine like terms to get 10x $^{2}$ + 8x - 8

D. 2f(x) - 2g(x)

Use the same 2f(x) and 2g(x) terms and this time just subtract.

You get 6x $^{2}$ - 4x + 4

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4 years ago

Use tape diagrams to find the solution of r/10 = 4.

nexus9112 [7]

Answer:

The solution is r=40.

Step-by-step explanation:

First, we identify the parts of the division:

"r" is the dividend of the division.

10 is the divisor

4 is the quotient.

To get the value of "r", we have to make a tape diagram where the divisor represents the number of equal-sized parts (boxes) and the quotient represents de quantity inside the boxes.

The tape diagram is made of 10 equal-sized parts of 4.

So the result is 10×4=40. The value of "r" is 40.

(See attached picture)