Question

Write the coordinates of the vertices of a triangle A'B'C' that results from a translation of triangle ABC two units to the right and four units down .

Answer 1

Answer:

A'(4,-6) , B'(0,1), C'(-2,-2)

Step-by-step explanation:

From the given graph the coordinates of ΔABC area A (2,-2), B(-2,5) and C(-4,2)

If a translation is applied on ΔABC two units to the right and four units down  to create ΔA'B'C'.

Then to find the coordinates of ΔA'B'C' will be we need to apply the translation rule

$(x,y)\rightarrow(x+2,y-4)$

Now, $A(2,-2)\rightarrow A'(2+2,-2-4)=A'(4,-6)$

$B(-2,5)\rightarrow B'(-2+2,5-4)=B'(0,1)$

and $C(-4,2)\rightarrow C'(-4+2,2-4)=C'(-2,-2)$