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DIA [1.3K]
3 years ago
12

Johnathan worked as a contractor for 18 years before he became permanently disabled and unable to work. Johnathan was 47 years o

ld and had planned to retire at age 60. His final annual salary was $71,740. His employer's rate of benefits is 1.6%. What is his annual disability benefit?
Mathematics
1 answer:
Phantasy [73]3 years ago
3 0

Answer: divide


Step-by-step explanation:


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The length of one side of a triangle is 2 feet less than three times the length of its second side. The length of the third side
seropon [69]

Answer:

  • 7 feet, 3 feet, 7.5 feet

Step-by-step explanation:

Let the sides be a, b and c.

<h3>Given</h3>

The length of one side of a triangle is 2 feet less than three times the length of its second side

  • a = 3b - 2

The length of the third side is 3/4 of the sum of the lengths of the first two sides:

  • c = (3/4)(a + b)

The perimeter of the triangle is 17.5 feet:

  • a + b + c = 17.5

<h3>Solution</h3>

Substitute a with b in the second equation:

  • c = (3/4)(3b - 2 + b) = (3/4)(4b - 2) = (3/4)(4b) - (3/4)(2) = 3b - 1.5

Now substitute a and c with b in the third equation and solve for b:

  • a + b + c = 17.5
  • 3b - 2 + b + 3b - 1.5 = 17.5
  • 7b - 3.5 = 17.5
  • 7b = 17.5 + 3.5
  • 7b = 21
  • b = 3

Find the value of a:

  • a = 3b - 2 = 3*3 - 2 = 9 - 2 = 7

Find the value of c:

  • c = 3b - 1.5 = 3*3 - 1.5 = 9 - 1.5 = 7.5

The sides of the triangle are:

  • a = 7 feet, b = 3 feet, c = 7.5 feet

8 0
1 year ago
- 3(1 – n) =-6 - 6n<br> Step by step please if possible
harkovskaia [24]
-3 + 3n = -6 - 6n. Expand the brackets
3n + 6n = -6 + 3. Collect like terms
9n = -3
n = -3/9 = -1/3
5 0
3 years ago
Help me with this!
andriy [413]
Answer:
Relation #2 and #4

3 0
3 years ago
Solve for x please. :)
solmaris [256]

Answer:

180-130=50

Step-by-step explanation:

done hope you like it

i use the 180 because its a straight line from the x to the 130

6 0
2 years ago
Heather solved this problem:
Ket [755]

Answer:

A tape diagram. StartFraction part Over whole EndFraction = StartFraction 300 Over 100 EndFraction = StartFraction 75

Step-by-step explanation:

4 0
2 years ago
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