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vivado [14]
3 years ago
13

What is the equation of the following line? Be sure to scroll down first to see

Mathematics
2 answers:
andriy [413]3 years ago
6 0

Answer:

y = 6x + 0

Step-by-step explanation:

Equation of a line

y = mx + c

Given

( 0 , 0) ( -1/2 , -3)

find the slope m

m = y2 - y1 / x2 - x1

x1 = 0

y1 = 0

x2 = -1/2

y2 = -3

Insert the values

m = y2 - y1 / x2 - x1

m = -3 - 0 / -1/2 - 0

= -3/-1/2

Minus cancels minus

= 3/1/2

= 3/1 ÷ 1/2

= 3/1 × 2/1

= 6/1

= 6

m = 6

Substitute any of the two points given into the equation of a line

y = mx + c

Where

y - intercept point y

x - intercept point x

m - slope of the line

c - intercept

(-1/2 , -3)

x = -1/2

y = -3

-3 = 6(-1/2) + c

-3 = -6/2 + c

-3 = -3 + c

-3 + 3 = c

c = 0

y = 6x + 0

The equation of the line is

y = 6x + 0

valentinak56 [21]3 years ago
5 0

Answer:

y= -6x on apex :)

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Suppose a population of honey bees in Ephraim, UT has an initial population of 2300 and 12 years later the population reaches 13
Rama09 [41]

Answer:

common ratio: 1.155

rate of growth: 15.5 %

Step-by-step explanation:

The model for exponential growth of population P looks like: P(t)=P_i(1+r)^t

where P(t) is the population at time "t",

P_i is the initial (starting) population

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and r is the rate of growth

Therefore, in our case we can replace specific values in this expression (including population after 12 years, and  initial population), and solve for the unknown common ratio and its related rate of growth:

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This (1+r) is the common ratio, that we are asked to round to the nearest thousandth, so we use: 1.155

We are also asked to find the rate of increase (r), and to express it in percent form. Therefore we use the last equation shown above to solve for "r" and express tin percent form:

1+r=1.155273\\r=1.155273-1=0.155273

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6 0
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Answer:

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From the given question, let the initial weight be represented by W, then:

I gained 3 pounds implies at that; 3 pounds was added to my initial weight. Thus, my present weight is my initial weight + 3 pounds.

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