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2 years ago

What is the equation of the following line? Be sure to scroll down first to see

Mathematics

2 answers:

andriy [413]2 years ago

6 0

Answer:

y = 6x + 0

Step-by-step explanation:

Equation of a line

y = mx + c

Given

( 0 , 0) ( -1/2 , -3)

find the slope m

m = y2 - y1 / x2 - x1

x1 = 0

y1 = 0

x2 = -1/2

y2 = -3

Insert the values

m = y2 - y1 / x2 - x1

m = -3 - 0 / -1/2 - 0

= -3/-1/2

Minus cancels minus

= 3/1/2

= 3/1 ÷ 1/2

= 3/1 × 2/1

= 6/1

= 6

m = 6

Substitute any of the two points given into the equation of a line

y = mx + c

Where

y - intercept point y

x - intercept point x

m - slope of the line

c - intercept

(-1/2 , -3)

x = -1/2

y = -3

-3 = 6(-1/2) + c

-3 = -6/2 + c

-3 = -3 + c

-3 + 3 = c

c = 0

y = 6x + 0

The equation of the line is

y = 6x + 0

valentinak56 [21]2 years ago

5 0

Answer:

y= -6x on apex :)

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Answer:

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Step-by-step explanation:

In this problem we have:

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$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

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2 years ago

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ycow [4]

Answer:

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Step-by-step explanation:

We have that:

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2 years ago

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astra-53 [7]

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