Answer:
Step-by-step explanation:
Let X be the SRS scores of students.
Given that X is normal with standard deviation about 6.5.
Mean difference = is desired
i.e. Z score should be
Std error = std deviation of sample = 0.447
b)
So std error must be 0.997 and sample size must be atleast 193 to get the difference of x bar and mu to lie within 1.3 points in either direction