<span>43.83g of nacl are required to </span><span>make 500.0 ml of a 1.500 m solution.</span>
The empirical formula of this compound is ![Fe_2O_3](https://tex.z-dn.net/?f=Fe_2O_3)
<h3>Empirical formula </h3>
To calculate the empirical formula of a compound, the value of moles of each element is needed.
As we have the information of the mass value, we will use the molar mass expression, which corresponds to:
![MM_O = 16g/mol\\MM_Fe = 55.8g/mol](https://tex.z-dn.net/?f=MM_O%20%3D%2016g%2Fmol%5C%5CMM_Fe%20%3D%2055.8g%2Fmol)
![MM = \frac{m}{mol}](https://tex.z-dn.net/?f=MM%20%3D%20%5Cfrac%7Bm%7D%7Bmol%7D)
![16 = \frac{4.8}{x}](https://tex.z-dn.net/?f=16%20%3D%20%5Cfrac%7B4.8%7D%7Bx%7D)
![x = 0.3mol](https://tex.z-dn.net/?f=x%20%3D%200.3mol)
![55.8=\frac{11.2}{x}\\x = 0.2](https://tex.z-dn.net/?f=55.8%3D%5Cfrac%7B11.2%7D%7Bx%7D%5C%5Cx%20%3D%200.2)
As the value of the empirical formula must be an integer, simply multiply the two values by a common factor:
![O = 0.3 \times 10 = 3\\Fe = 0.2 \times 10 = 2](https://tex.z-dn.net/?f=O%20%3D%200.3%20%5Ctimes%2010%20%3D%203%5C%5CFe%20%3D%200.2%20%5Ctimes%2010%20%3D%202)
![Fe_2O_3](https://tex.z-dn.net/?f=Fe_2O_3)
So, the empirical formula of this compound is
.
Learn more about empirical formula: brainly.com/question/1247523
Answer
2.7956 * 10^19 photons
Givens
- Wavelength = λ = 525 * 10^-9 meters [1 nmeter = 1*10^-9 meters]
- c = 3 * 10^8 meters
- E = ???
- W = 100 watts
- t = 1 second
- h= plank's Constant = 6.26 * 10^-34 J*s
Formula
E = h * c / λ
W = E / t
Solution
E = 6.26 * 10^-34 j*s * 3 * 10^8 m/s /525 * 10^-9 (m)
The meters cancel out. So do the seconds. You are left with Joules as you should be.
E = 3.577 * 10^-18 Joules
What you have found is the energy of 1 photon.
Now you have to find the Joules from the watts.
W = E/t
100 * 1 second = 100 joules
1 photon contains 3.577 * 10 ^ - 18 Joules
x photon = 100 joules
1/x = 3.577 * 10^-18 / 100 Cross multiply
100 = 3.577 * 10 ^ - 18 * x Divide both sides by 3.577 * 10 ^ - 18
100/3.577 * 10 ^ - 18 = 3.577 * 10 ^ - 18x / 3.577 * 10 ^ - 18
2.7956 * 10^19 photons = x
The domain that is an onion is the <span>Eukaryote.
</span>
Answer:
Atomic radius of sodium = 227 pm
Atomic radius of potassium = 280 pm
Explanation:
Atomic radii trend along group:
As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
Consider the example of sodium and potassium.
Sodium is present above the potassium with in same group i.e, group one.
The atomic number of sodium is 11 and potassium 19.
So potassium will have larger atomic radius as compared to sodium.
Atomic radius of sodium = 227 pm
Atomic radius of potassium = 280 pm